For spherical polar coordinate system1-Zr Zr.еxp(-X2)sin 6Cosø4/2 a2aaJu„v„dv = 6 =?px

ψpx2a=142Za3/2exrp(-Zr2a)(Zra)sin θcos∅Now, ∫xx=∫-∞+∞ψpxψpx dV=∫-∞+∞ψpx2dV

Answered: For spherical polar coordinate system -…

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For spherical polar coordinate system - Zr,Zr, (3² exp(x)sin Cosó 4/2 a 1 2a a Ju„VdV = 8 = ?

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter7: Molecular Structures

Section: Chapter Questions

Problem 65QRT

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Question

For spherical polar coordinate system
1
-Zr Zr.
еxp(-
X2)sin 6Cosø
4/2 a
2a
a
Ju„v„dv = 6 =?
px

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