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- Let X be a random variable with range {20,30,50} and probability distribution P(X=20) = 0.25,P(X=30) = 0.25, and P(X=50) = 0.5. What is the expected value of X?Random variable X is independent of random variable Y, and X-B(10, 0.3), Y-B(20, 0.3), compute P(X=1 | X+Y=4).The probability of having a red color ball is 15%. The boy selected four submitted balls at random, let X be a random variable indicating the number of red color balls out of those balls selected by the boy. Identify and compute the expected value for the random variable X, i.e. E(X).
- For a large population of people, the probability distribution for the random variable X = the number of meals a person ate yesterday and the assigned probabilities is given below: Meals, X Probability (a) Find P(X= 5), the probability that a randomly selected person ate 5 meals yesterday. P(X= 5) = 1 3 4 5 0.17 0.35 0.24 0.17 ? (b) Find P(X ≤ 2), the probability that a randomly selected person ate 2 or fewer meals yesterday. P(X ≤ 2) = (c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday. P = (d) Find P(X > 1), the probability that a randomly selected person ate more than 1 meal yesterday. P(X > 1) =Let Y be a binomial random variable with n = 10 and p = 0.3. (a) P(3 < Y < 5) = P(3 ≤ Y < 5) = (b) P(3 < Y ≤ 5) = P(3 ≤ Y ≤ 5) =Let X be a normal random variable with = 10 and = 2. Find the values of P(X < 11) b. P(X > 8) P(7 < X < 9)
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