For SN1Explain if 3o ( tertiary) alkyl halides reacted (fastest or slowest) explain why. Be sure to explain if alkyl halides did not react or did react and why.3o (tertiary) compounds listed are: 2-chloro-2-methylpropane (see picture) Base your explanations on the following considerations: the nature of leaving group, the effect of structure, steric hindrance and any other feature. CI lar nc MedaSnlReactivity of Alkyl Halides with Nal in Acetone#CompoundRoom temp.50 °CProduaTimeName1-chlorobutaneclassR 1-bromobutaneclassStructureTimeObs.Obs.Structur0SsecपिसाMow0-Sse yellow2-chlorobutane3.class2-bromobutaneclass 2Form0-sYdlow4.Clecr2-chloro-2-methylpropaneclass 3"1-chloro-2-butene(crotylchloride)classbenzylchlorideclass8.0-5Sightkoie / SDarkerIn0-Sinitebromobenzeneclass9.BrClearKlealClearbromocyclopentaneclass 210 bromocyclohexaneclass 2earClear6.

In unimolecular nucleophilic substitution reaction, the intermediate formed is carbocation. More stable the intermediate more fast will be the reaction. Stability of carbocation: Tertiary carbocation > secondary carbocation > primary carbocation. In case of 2-chloro-2-methylpropane, the carbocation formed is tertiary which is most stable. Thus 2-chloro-2-methylpropane will react faster in under SN1 mechanism. Steric hindrance in reactant favors the SN1 reaction. More number of branched carbon atom more will be the stability of carbocation. Cl- being good leaving group, enhance the rate of reaction.