For R1=172, R2=177, R3-214, R4-450, R5-435, R6-455, V1=3 V & 11=4 A in the shown circuit, using the superposition principle find the following: io R6 www I1 R2 + V1 Vo R4 R3 + Iol (in ampere) due to V1 only= (Note that Io-Io1+I02, where Iol is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io-Io1+Io2, where Iol is due to V1 and Io2 is due to I1) Vo2 (in volt) due to Il only= (Note that Vo-Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) R1

For R1=172, R2=177, R3-214, R4-450, R5-435, R6-455, V1=3 V & 11=4 A in the shown circuit, using the superposition principle find the following: io R6 www I1 R2 + V1 Vo R4 R3 + Iol (in ampere) due to V1 only= (Note that Io-Io1+I02, where Iol is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io-Io1+Io2, where Iol is due to V1 and Io2 is due to I1) Vo2 (in volt) due to Il only= (Note that Vo-Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) R1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Requirements: • Find Current R1 and R2 And find the voltage in R3 5. Superposition
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QUESTION 1 Refer to the given circuit below. Determine the equivalent resistance across terminals a and d if R1 = 3 0 R2 = 6 0 R3 = 2 0 R4 = 8 0 R5 = 3 0 R6 = 70 R7 = 2 0 R8 = 70 a R2 R4 R6 Rg R1 R3. R5 R7 d
Find R1,R2,R3
For R1=5, R2=1, R3=3, R4=9, R5=8, R6=2, R7=7, R8=4, V1=20 V, V2=51 V, 15=1 A and 16=6 A in the shown circuit, find the following: R6 R5 V2 15 CR4 R8 R3 R7 ER2 Vi R1 16 i1 (in ampere)= i2 (in ampere)= i3 (in ampere)= 14 (in ampere)= Io (in ampere)= (+1) ww
For R1=285, R2=328, R3-414, R4=240, R5=160, R6-400, V1=3 V & I1=1 A in the shown circuit, using the superposition principle find the following: + V1 R5 Vo R4 + R6 w I1 R3 io R2 m ZR1 Iol (in ampere) due to V1 only= (Note that Io=Io1+Io2, where Iol is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Io1+Io2, where Iol is due to V1 and Io2 is due to I1) Vo2 (in volt) due to Il only= (Note that Vo=Vol+Vo2, where Vol is due to V1 and Vo2 is due to I1)
The dynamic part of the state space representation of the following circuit with R₁ = 20 R₂ = 20 L₁ = 0.5H L₂ = 0.25H is O 1. O 2. None of the answers O 3. O 4. O 5. -4 M=1 = 0 R₁ ww -2 [22]=16² 0 0 -0.5 L₁ 5 2 4-6 +64 1₂ In -8 4-6 90+4 = 0 →→ 30 4+4 [²]+[+]¹ -0.25] [142] + [0.25] ¹ L₂ 1/12
For given value of the circuit, Vsupply = 120 V, and with R₁= 2002, R₂=30.0, R3=75, R4=30N, R5= 200, R6-400 and R7=12002? • What is the total resistor? 60 Ω 100 Ω 120 Ω 435 Ω V1 -120 V R1 m 2002 in R3 750 R7 12002 R6 4002 R2 2300 R4 300 R5 200
Using loop/mesh analysis, find the loop2 equation. Given R1=5 Ohm, R2= 10 Ohm, R3= 5 Ohm, R4 = 1 Ohm. R3 on BR Ry R. 20V Select one: O a. NONE OF THESE O b. -12 11 + 10 12 = 10 Oc 10 11 - 14 12 = -20 Od -15 1 - 10 12 = 10 Ce 10 11- 16 12 = -20
For R1=478, R2=154, R3=169, R4-400, R5=195, R6-335, V1=7 V & 11=2 A in the shown circuit, using the superposition principle find the following: R6 Il R2 m V1 VR4 R3 RI Iol (in ampere) due to V1 only= (Note that Io-Io1+102, where Io1 is due to V1 and Io2 is due to I1) Vol (in volt) due to V1 only= (Note that Vo-Vo1+Vo2, where Vol is due to V1 and Vo2 is due to I1) Io2 (in ampere) due to Il only= (Note that Io=Io1+102, where Io1 is due to V1 and Io2 is due to I1) Vo2 (in volt) due to 11 only= (Note that Vo=V61+V02, where Vol is due to V1 and Vo2 is due to I1)