For quality control, a chemist analyses the vitamin C (molecular formula CH&O6) content of a new brand of fruit juice. The reaction is: C6H&O6(aq) + I3 (aq) CH6O6(aq) + 2H (aq) +31 (aq) A 20.00 mL sample of the fruit juice was made up to 250.0 mL with pure water in a volumetric flask. 25.00 mL aliquots of the diluted fruit juice were then placed in a conical flask and titrated with a solution in which [I3] 2.00 x 104 mol L1 An average titre of 15.65 mL was obtained. (a) Calculate the amount of I3 present in the average titre, in mole. (b) Calculate the amount of vitamin C present in each 25.00 mL aliquot, in mole. (c) Calculate the concentration of vitamin C in the original (undiluted) sample of fruit juice in mole per litre.
For quality control, a chemist analyses the vitamin C (molecular formula CH&O6) content of a new brand of fruit juice. The reaction is: C6H&O6(aq) + I3 (aq) CH6O6(aq) + 2H (aq) +31 (aq) A 20.00 mL sample of the fruit juice was made up to 250.0 mL with pure water in a volumetric flask. 25.00 mL aliquots of the diluted fruit juice were then placed in a conical flask and titrated with a solution in which [I3] 2.00 x 104 mol L1 An average titre of 15.65 mL was obtained. (a) Calculate the amount of I3 present in the average titre, in mole. (b) Calculate the amount of vitamin C present in each 25.00 mL aliquot, in mole. (c) Calculate the concentration of vitamin C in the original (undiluted) sample of fruit juice in mole per litre.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For quality control, a chemist analyses the vitamin C (molecular formula CH&O6) content of a new brand of fruit juice.
The reaction is:
C6H&O6(aq) + I3 (aq)
CH6O6(aq) + 2H (aq) +31 (aq)
A 20.00 mL sample of the fruit juice was made up to 250.0 mL with pure water in a volumetric flask. 25.00 mL aliquots
of the diluted fruit juice were then placed in a conical flask and titrated with a solution in which
[I3] 2.00 x 104 mol L1
An average titre of 15.65 mL was obtained.
(a) Calculate the amount of I3 present in the average titre, in mole.
(b) Calculate the amount of vitamin C present in each 25.00 mL aliquot, in mole.
(c) Calculate the concentration of vitamin C in the original (undiluted) sample of fruit juice in mole per litre.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2177996d-7ac8-4660-978e-7f744330ef7d%2Fdb9d74ed-6f4c-4eb8-a66b-d54c6a6f1c85%2Frxg7w2.jpeg&w=3840&q=75)
Transcribed Image Text:For quality control, a chemist analyses the vitamin C (molecular formula CH&O6) content of a new brand of fruit juice.
The reaction is:
C6H&O6(aq) + I3 (aq)
CH6O6(aq) + 2H (aq) +31 (aq)
A 20.00 mL sample of the fruit juice was made up to 250.0 mL with pure water in a volumetric flask. 25.00 mL aliquots
of the diluted fruit juice were then placed in a conical flask and titrated with a solution in which
[I3] 2.00 x 104 mol L1
An average titre of 15.65 mL was obtained.
(a) Calculate the amount of I3 present in the average titre, in mole.
(b) Calculate the amount of vitamin C present in each 25.00 mL aliquot, in mole.
(c) Calculate the concentration of vitamin C in the original (undiluted) sample of fruit juice in mole per litre.
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