For problem 24.49 of the text, calculate the initial speed of the third electron in m/s using a separation of the other two electrons of 0.56 m. (5 sig. figs.)
Q: (3) Two protons are initially both traveling with velocity ở = -1.91 x 10°m/sj while sepa- rated by…
A: Velocity of both protons = u→=-1.91×106m/s j^ Initial separation = 54.8 fm = 54.8 ×10-15 m
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A: Separation, d = 4.7 mnVoltage, ∆V = 78 VCharge on proton, Q = 1.6×10-19 C = 1eEnergy in eV, KE = ?
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- To find out how big or small the value of 1 C is, calculate:a) How many electrons are needed to generate a charge of 1 C tsb.b) What is the mass of all these electrons?c) If two loads of 1 C each are 1 km apart, calculate the repulsion force between the two payloads.(b) What is the electric potential energy of two electrons separated by 4.00 nm? If the separation increases, does the potential energy increase or decrease? (2)A carbon nucleus and an iron nucleus are initially located 5.15 nm apart from one another. How much work would it take to move the carbon nucleus to a new distance of 1.28 nm from the iron nucleus? O 158.0 eV O 210.7 eV O 105.4 eV O 131.7 eV
- let a parallel plate capacitor be in the vacuum with one plate cathode located at x=0 emitting electrons which are collected at the other plate anode located at x=d the arrangement makes up a vacuum diode lets the volume charge density within the capacitor be given by pv(x)=-(4/9) E0V0d^-4/3 x^-2/3 C/m^3 where the cathode is located at x=0 and the anode at x=d . The voltage between the anode and the cathode is V0 and the total charge in 1m^2 cross section is -12 nC .1 find the Vo if d = 6mm . 2 find d if vo=5v . Calculus Please help as soon as possible thank youIn a simple model of a hydrogen atom, the single electron orbits the single proton (the nucleus) in a circular path. Calculate (a) the electric potential set up by the proton at the orbital radius of 52.9 pm, (b) the electric potential energy of the atom, and (c) the kinetic energy of the electron. (d) How much energy is required to ionize the atom (that is, to remove the electron to an infinite distance with no kinetic energy)? Give the energies in electron-volts.What is the mechanical potential energy of an electron at the center of a gold nucleus 197 79Au given that the nucleus is a uniformly charged sphere of radius R = 1.2 A^(1/3) fm.
- Two electrons are fixed 1.70 cm apart. Another electron is shot from infinity and stops midway between the two as the figure shows. What is its initial speed?(a) What is the electric potential energy of two electrons separated by 1.94 nm? (b) What would be it be if the separation was doubled?Coulomb's Law yields an expression for the energy of interaction for a pair of point charges. V = 2.31x10^-19 Q1Q2 r V is the energy (in J) required to bring the two charges from infinite distance separation to distance r (in nm).Q1 and Q2 are the charges in terms of electrons.(i.e. the constant in the above expression is 2.31×10-19 J nm electrons-2) For a group of "point" charges (e.g. ions) the total energy of interaction is the sum of the interaction energies for the individual pairs.Calculate the energy of interaction for the square arrangement of ions shown in the diagram below. d = 0.545 nm
- In the figure below, determine the point (other than infinity) at which the electric field is zero. (Let q, = -1.65 µC and q2 = 6.90 µc.) -1.00 m-fig 5 Me= In Figure 5. the electron on the right side is fixed. and the one on the left side has initial velocity 10' m/s towards the first electron at the distance shown. Determine the final speed of the mobile electron when it is far away from the fixed one.A completely ionized beryllium atom (net charge = +4e) is accelerated through a potential difference of 6.0 V. What is the increase in kinetic energy of the atom? a. 0 eV b. 0.67 eVc. 12 eVd. 24 eV