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For ozone at 25 °C, AG; = 163.2 kJ/mol. a) At 25 °C, compute the equilibrium constant K, for the reaction 302(g) 203(g) b) Assuming that the advancement at equilibrium, če, is very much less than unity, show that Še = /pK. (Let the original number of moles of O, be three, and of O, be zero.) c) Calculate K, at 5 atm and K..

For ozone at 25 °C, AG; = 163.2 kJ/mol. a) At 25 °C, compute the equilibrium constant K, for the reaction 302(g) 203(g) b) Assuming that the advancement at equilibrium, če, is very much less than unity, show that Še = /pK. (Let the original number of moles of O, be three, and of O, be zero.) c) Calculate K, at 5 atm and K..

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The correct answers are;

a. 6.6x10^-58

c. Kx= 3.3x10^-57 ; Kc= 1.6x10^-56

 

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For ozone at 25 °C, AG; = 163.2 kJ/mol. a) At 25 °C, compute the equilibrium constant K, for the reaction 302(g) 203(g) b) Assuming that the advancement at equilibrium, če, is very much less than unity, show that Še = /pK,. (Let the original number of moles of O, be three, and of O, be zero.) c) Calculate K, at 5 atm and K..
Transcribed Image Text:For ozone at 25 °C, AG; = 163.2 kJ/mol. a) At 25 °C, compute the equilibrium constant K, for the reaction 302(g) 203(g) b) Assuming that the advancement at equilibrium, če, is very much less than unity, show that Še = /pK,. (Let the original number of moles of O, be three, and of O, be zero.) c) Calculate K, at 5 atm and K..
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