4) Given that: N204 = 2 NO2 → K = 0.212 at 100 C. What is K for: 2 N204 = 4 NO2 at 100 C? a) 0.212 b) 4.45 x 102 c) more information needed d) 4.24 x 10-'
4) Given that: N204 = 2 NO2 → K = 0.212 at 100 C. What is K for: 2 N204 = 4 NO2 at 100 C? a) 0.212 b) 4.45 x 102 c) more information needed d) 4.24 x 10-'
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![**Equilibrium Constants Problem**
**Question:**
Given the reaction:
\[ N_2O_4 \rightleftharpoons 2 NO_2 \]
The equilibrium constant \( K \) at 100°C is 0.212.
What is the equilibrium constant \( K \) for the reaction:
\[ 2 N_2O_4 \rightleftharpoons 4 NO_2 \]
at 100°C?
**Options:**
a) 0.212
b) \( 4.45 \times 10^{-2} \)
c) more information needed
d) \( 4.24 \times 10^{-1} \)
---
**Explanation:**
When the coefficients in a balanced chemical equation are multiplied by a factor, the equilibrium constant is influenced by this change. If the entire balanced equation is multiplied by a factor \( n \), the new equilibrium constant will be the original \( K \) raised to the power of \( n \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07d00ca0-0430-458f-a009-3ccbf8c49c5a%2F911dd8fb-41ac-48bc-b9e7-f3687af72f8c%2Fixz4oyte_processed.png&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constants Problem**
**Question:**
Given the reaction:
\[ N_2O_4 \rightleftharpoons 2 NO_2 \]
The equilibrium constant \( K \) at 100°C is 0.212.
What is the equilibrium constant \( K \) for the reaction:
\[ 2 N_2O_4 \rightleftharpoons 4 NO_2 \]
at 100°C?
**Options:**
a) 0.212
b) \( 4.45 \times 10^{-2} \)
c) more information needed
d) \( 4.24 \times 10^{-1} \)
---
**Explanation:**
When the coefficients in a balanced chemical equation are multiplied by a factor, the equilibrium constant is influenced by this change. If the entire balanced equation is multiplied by a factor \( n \), the new equilibrium constant will be the original \( K \) raised to the power of \( n \).
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