For | cos 3x cos 4x dx :

Q: Evaluate sec(4x) tan(4x)dx Select one: sec(4x) a. +C sec(z) b. +C 4 C. sec(4x) + C d. 4 sec(4x) + C

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Q: 11. cos4x-cos2 dx sin4x-cos2x

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Q: Differentiate y = In (cos² 3x).

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Q: cos (2x) dx sinx+cosx COS Evaluate:

A: the given integral is: ∫cos(2x)sinx+cosxdx we have to evaluate the given integral.

Q: Evaluate (3x + cos 4x) dx

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Q: The function y = 2x – cos x have two variables (x and y), these variables called

A: Here, the given equation is y=2x-cosx , which is a function of two variables(x and y). The name of…

Q: Evaluate sin dx

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Q: Use the method of substitution to evaluate | 2x cos x? dx.

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Q: Find a suitable substitution for evaluating ∫tan x sec2 x dx andexplain your choice.

A: we have to integrate the following integral using a suitable substitution. ∫tanx.sec2xdx

Q: 3. tan x dx

A: Formula: tan2x=sec2x-1

Q: Y= 5-e- COSX by %3D

A: Given: y=5-e6y=cosx( This question is don't have to specify word  find  and how to find the answer)

Q: Ssin8 (3z) cos5 (3z) dz

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Q: Evaluate Set 7x cos (6x) dx. Sex cos (6x) dx =

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Q: dx xtan x Evaluate secx+cosr

A: Explanation of the answer is as follows

Q: y = cos(-4x)

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Q: dx It sin x-cos x COS

A: To evaluate:∫dx1+sinx-cosx Solution: We know,cos2x=1-tan2x1+tan2x     ...(1)sin2x=2tanx1+tan2x…