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For numbers 3-5, check the given RLC circuit: A) B) A) B) +81 = 0 3. The differential equation to solve for the subsequent current is given by d²1 dl d²1 dI +4 dt² dt d²1 1 dl + dt² 4 dt +2 +81 10 dt² dt d²1 1 dl += dt² 4 dt 4. Assuming that there is no current and charge when the voltage is first applied, what is L{1}? 8s +32 32 4s² + s + 16 8 4s² + s + 16 10s s² + 4s +8 s² + 4s +8 5. The subsequent current in the circuit is +41 8 10 V A) I(t) = 4e-8t cos √2 t B) I(t) = 4e-2t sin 2 t 50 HH 10-¹ C C) D) D) 1.25 H C) D) +41 = 0 I(t) = 4e-8t sin √2t I(t) = 4e-2t cos 2 t

For numbers 3-5, check the given RLC circuit: A) B) A) B) +81 = 0 3. The differential equation to solve for the subsequent current is given by d²1 dl d²1 dI +4 dt² dt d²1 1 dl + dt² 4 dt +2 +81 10 dt² dt d²1 1 dl += dt² 4 dt 4. Assuming that there is no current and charge when the voltage is first applied, what is L{1}? 8s +32 32 4s² + s + 16 8 4s² + s + 16 10s s² + 4s +8 s² + 4s +8 5. The subsequent current in the circuit is +41 8 10 V A) I(t) = 4e-8t cos √2 t B) I(t) = 4e-2t sin 2 t 50 HH 10-¹ C C) D) D) 1.25 H C) D) +41 = 0 I(t) = 4e-8t sin √2t I(t) = 4e-2t cos 2 t

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For numbers 3-5, check the given RLC circuit: A) B) A) B) d²1 dI +4 dt² dt d²1 1 dl + dt² 4 dt 3. The differential equation to solve for the subsequent current is given by d²1 dl +2 +81 10 dt² dt d²1 1 dl + +41 = 0 dt² 4 dt 4. Assuming that there is no current and charge when the voltage is first applied, what is L{1}? 8s +32 32 4s² + s + 16 8 4s² + s + 16 10s s² + 4s +8 s² + 4s +8 +81 = 0 +41 8 10 V 5. The subsequent current in the circuit is A) I(t) = 4e-8t cos √2 t B) I(t) = 4e-2t sin 2 t 50 m HH 10¹ C C) D) D) 1.25 H C) D) I(t) = 4e-8t sin √2t I(t) = 4e-2t cos 2 t
Transcribed Image Text:For numbers 3-5, check the given RLC circuit: A) B) A) B) d²1 dI +4 dt² dt d²1 1 dl + dt² 4 dt 3. The differential equation to solve for the subsequent current is given by d²1 dl +2 +81 10 dt² dt d²1 1 dl + +41 = 0 dt² 4 dt 4. Assuming that there is no current and charge when the voltage is first applied, what is L{1}? 8s +32 32 4s² + s + 16 8 4s² + s + 16 10s s² + 4s +8 s² + 4s +8 +81 = 0 +41 8 10 V 5. The subsequent current in the circuit is A) I(t) = 4e-8t cos √2 t B) I(t) = 4e-2t sin 2 t 50 m HH 10¹ C C) D) D) 1.25 H C) D) I(t) = 4e-8t sin √2t I(t) = 4e-2t cos 2 t
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