For numbers 17-19: Refer to the figure and given below. Given: Triangles ABD and ADE are inscribed in OF with AB = BD. m21 = (12x – 8)°, and mL2 = (3x+ 8)° %3D A®©D 17. Which of the equations below can be used to determine the value of x? A. mz1 +mz2 = 180° B. mz1+90° = 180° C. mz1 + mz3 =90° D. mz1 + m22 +90° = 180° AB©0 18. What is the value of x? A. 18 В. 12 С.8 D. 6 O©D 19. What is the measure of LEDB and BAE respectivley? A. MLEDB = 26° and MLBAE = 64° B. MLEDB = 52° and mLBAE = 128° C. MZEDB = 71° and mLBAE = 109° D. mLEDB = 90° and mLBAE = 90°
For numbers 17-19: Refer to the figure and given below. Given: Triangles ABD and ADE are inscribed in OF with AB = BD. m21 = (12x – 8)°, and mL2 = (3x+ 8)° %3D A®©D 17. Which of the equations below can be used to determine the value of x? A. mz1 +mz2 = 180° B. mz1+90° = 180° C. mz1 + mz3 =90° D. mz1 + m22 +90° = 180° AB©0 18. What is the value of x? A. 18 В. 12 С.8 D. 6 O©D 19. What is the measure of LEDB and BAE respectivley? A. MLEDB = 26° and MLBAE = 64° B. MLEDB = 52° and mLBAE = 128° C. MZEDB = 71° and mLBAE = 109° D. mLEDB = 90° and mLBAE = 90°
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
I. 17-20
![For numbers 17-19: Refer to the figure and given below.
Given: Triangles ABD and ADE are inscribed in OF with AB = BD. m21 =
(12x – 8)°,
and mL2 =
(3x + 8)°
®©0 17.
Which of the equations below can be used to determine the value of x?
A. m21 +mL2 = 180°
B. m1 +90° = 180°
C. m21 + mz3 =90°
D. mz1 + m22 + 90° = 180°
®©0 18.
What is the value of x?
A. 18
В. 12
С.8
D. 6
D00 19.
What is the measure of LEDB and LBAE respectivley?
A. MLEDB = 26° and mLBAE = 64°
B. MLEDB = 52° and mLBAE = 128°
C. MLEDB = 71° and mLBAE = 109°
D. MLEDB = 90° and mLBAE = 90°
AB©D 20. Using OC at the right, arrange the statements and reasons into sequential order
to prove that MT = TN and MQ = QN given that CQI MN.
1. CT CT by reflexive property
II. MC CN by All radii of a circle are congruent.
II. MQ = QN since congruent cnetral angles have congruent arcs.
IV. A MCT = ANCT by Hypotenuse Leg Congruence Theorem
V. MT TN and 21 22 by CPCTC
A. I, II, IV, II, V
B. I,I, IV, V, II
C. II, I, V.I, V, II
D. IV, V, I, II, I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca479629-cc84-4c0f-8ffc-a423c8126e1b%2F49bb41e0-ff92-44df-81b5-aade8075684c%2Fuw6l8q8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For numbers 17-19: Refer to the figure and given below.
Given: Triangles ABD and ADE are inscribed in OF with AB = BD. m21 =
(12x – 8)°,
and mL2 =
(3x + 8)°
®©0 17.
Which of the equations below can be used to determine the value of x?
A. m21 +mL2 = 180°
B. m1 +90° = 180°
C. m21 + mz3 =90°
D. mz1 + m22 + 90° = 180°
®©0 18.
What is the value of x?
A. 18
В. 12
С.8
D. 6
D00 19.
What is the measure of LEDB and LBAE respectivley?
A. MLEDB = 26° and mLBAE = 64°
B. MLEDB = 52° and mLBAE = 128°
C. MLEDB = 71° and mLBAE = 109°
D. MLEDB = 90° and mLBAE = 90°
AB©D 20. Using OC at the right, arrange the statements and reasons into sequential order
to prove that MT = TN and MQ = QN given that CQI MN.
1. CT CT by reflexive property
II. MC CN by All radii of a circle are congruent.
II. MQ = QN since congruent cnetral angles have congruent arcs.
IV. A MCT = ANCT by Hypotenuse Leg Congruence Theorem
V. MT TN and 21 22 by CPCTC
A. I, II, IV, II, V
B. I,I, IV, V, II
C. II, I, V.I, V, II
D. IV, V, I, II, I
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