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Suppose the mean number of people attending all 2017 Veterans Day celebrations held in Virginia is 182 with a standard deviation of 37 people. A few of the celebrations are huge, and hence the distribution is skewed heavily to the right. If a simple random sample of 54 Veterans Day celebrations held in Virginia is selected and the number of people in attendance determined for each, describe completely the sampling distribution of, the resulting mean number of people attending for this sample of 54 Veterans Day celebrations held in Virginia. 18 Do we have a simple random sample? No Yes DOD Is the population normally distributed? No Yes 20 Does the problem indicate there is heavy skewness? No Yes 19

Suppose the mean number of people attending all 2017 Veterans Day celebrations held in Virginia is 182 with a standard deviation of 37 people. A few of the celebrations are huge, and hence the distribution is skewed heavily to the right. If a simple random sample of 54 Veterans Day celebrations held in Virginia is selected and the number of people in attendance determined for each, describe completely the sampling distribution of, the resulting mean number of people attending for this sample of 54 Veterans Day celebrations held in Virginia. 18 Do we have a simple random sample? No Yes DOD Is the population normally distributed? No Yes 20 Does the problem indicate there is heavy skewness? No Yes 19

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please help with part #18, 19, and 20

### Sampling Distributions and Skewness in Veterans Day Celebrations Data The problem focuses on describing the sampling distribution of the mean number of people attending Veterans Day celebrations in Virginia in 2017. Let's break it down step-by-step. #### Scenario Suppose the mean number of people attending all 2017 Veterans Day celebrations held in Virginia is 182 with a standard deviation of 37 people. A few of the celebrations are huge, and hence the distribution is skewed heavily to the right. If a simple random sample of 54 Veterans Day celebrations held in Virginia is selected and the number of people in attendance determined for each, describe completely the sampling distribution of the resulting mean number of people attending for this sample of 54 Veterans Day celebrations held in Virginia. ### Questions **Question 18: Do we have a simple random sample?** - Option 1: No - Option 2: Yes **Question 19: Is the population normally distributed?** - Option 1: No - Option 2: Yes **Question 20: Does the problem indicate there is heavy skewness?** - Option 1: No - Option 2: Yes ### Explanation 1. **Simple Random Sample (Question 18):** - A simple random sample means that every member of the entire population has an equal chance of being selected. - In this scenario, if the sample of 54 Veterans Day celebrations was indeed selected randomly, then the answer to Question 18 should be "Yes". 2. **Normal Distribution of the Population (Question 19):** - The statement mentions that the distribution is skewed heavily to the right, indicating that the population distribution is not normally distributed. - Therefore, the answer to Question 19 should be "No". 3. **Indication of Heavy Skewness (Question 20):** - The problem explicitly states that the distribution is skewed heavily to the right. - Hence, the answer to Question 20 should be "Yes". ### Additional Insights on Sampling Distribution: Despite the skewness of the population distribution, the sampling distribution of the sample mean will approximate a normal distribution due to the Central Limit Theorem, provided the sample size is sufficiently large (n=54 in this case is generally considered large). - **Mean of the Sampling Distribution:** The same as the population mean: 182. - **Standard Deviation of the Sampling Distribution (Standard Error):**
Transcribed Image Text:### Sampling Distributions and Skewness in Veterans Day Celebrations Data The problem focuses on describing the sampling distribution of the mean number of people attending Veterans Day celebrations in Virginia in 2017. Let's break it down step-by-step. #### Scenario Suppose the mean number of people attending all 2017 Veterans Day celebrations held in Virginia is 182 with a standard deviation of 37 people. A few of the celebrations are huge, and hence the distribution is skewed heavily to the right. If a simple random sample of 54 Veterans Day celebrations held in Virginia is selected and the number of people in attendance determined for each, describe completely the sampling distribution of the resulting mean number of people attending for this sample of 54 Veterans Day celebrations held in Virginia. ### Questions **Question 18: Do we have a simple random sample?** - Option 1: No - Option 2: Yes **Question 19: Is the population normally distributed?** - Option 1: No - Option 2: Yes **Question 20: Does the problem indicate there is heavy skewness?** - Option 1: No - Option 2: Yes ### Explanation 1. **Simple Random Sample (Question 18):** - A simple random sample means that every member of the entire population has an equal chance of being selected. - In this scenario, if the sample of 54 Veterans Day celebrations was indeed selected randomly, then the answer to Question 18 should be "Yes". 2. **Normal Distribution of the Population (Question 19):** - The statement mentions that the distribution is skewed heavily to the right, indicating that the population distribution is not normally distributed. - Therefore, the answer to Question 19 should be "No". 3. **Indication of Heavy Skewness (Question 20):** - The problem explicitly states that the distribution is skewed heavily to the right. - Hence, the answer to Question 20 should be "Yes". ### Additional Insights on Sampling Distribution: Despite the skewness of the population distribution, the sampling distribution of the sample mean will approximate a normal distribution due to the Central Limit Theorem, provided the sample size is sufficiently large (n=54 in this case is generally considered large). - **Mean of the Sampling Distribution:** The same as the population mean: 182. - **Standard Deviation of the Sampling Distribution (Standard Error):**
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