For number 1 and 2. Use the method of joints to determine the force in each member of the roof truss shown. State whether each member is in tension or compression. 6 m- 1.2 kN - 6 m -6m- 2.4 kN 2.4 kN 1.2 kN 7.5 m Answers: AB = 6.24 kN C: AC = 2.76 kN T; BC = 2.50 kN C:; BD = 4.16 kN C; CD = 1.867 kN T; CE = 2.88 kN T; DE = 3.75 kN C: DF = 0; EF = 1.20 kN C m SITY

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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1 and 2 please

For number 1 and 2. Use the method of joints to determine the force in each member of
the roof truss shown. State whether each member is in tension or compression.
6 m-
1.2 kN
6 m--6 m –
2.4 kN
2.4 kN
1.2 kN
7.5 m
BV
Answers:
AB = 6.24 kN C; AC = 2.76 kN T;
BC = 2.50 kN C; BD = 4.16 kN C:
CD = 1.867 kNT; CE = 2.88 kN T;
DE = 3.75 kN C; DF = 0; EF = 1.20 kN C
AV
9 m
9 m
1.
9.6 kN
10.5 kN
10.5 kN
5.7 kN
5.7 kN
24 m
3.8 m-
- 3.2 m 3.2 m -
-3.8 m -
2.
Answers:
AB = 47.2 kN C; AC = 44.6 kN T; BC = 10.50 kN C;
BD = 47.2 kN C; CD = 17.50 kN T; CE = 30.6 kN T;
DE = 0.
SITY
Transcribed Image Text:For number 1 and 2. Use the method of joints to determine the force in each member of the roof truss shown. State whether each member is in tension or compression. 6 m- 1.2 kN 6 m--6 m – 2.4 kN 2.4 kN 1.2 kN 7.5 m BV Answers: AB = 6.24 kN C; AC = 2.76 kN T; BC = 2.50 kN C; BD = 4.16 kN C: CD = 1.867 kNT; CE = 2.88 kN T; DE = 3.75 kN C; DF = 0; EF = 1.20 kN C AV 9 m 9 m 1. 9.6 kN 10.5 kN 10.5 kN 5.7 kN 5.7 kN 24 m 3.8 m- - 3.2 m 3.2 m - -3.8 m - 2. Answers: AB = 47.2 kN C; AC = 44.6 kN T; BC = 10.50 kN C; BD = 47.2 kN C; CD = 17.50 kN T; CE = 30.6 kN T; DE = 0. SITY
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