For items 10-12. The decomposition of NH4Cl (s) at a given temperature of 548 K, the Kp = 0.01072. NH4Cl (s) NH4 (g) + HCl (g) = 10. If 10.00 g of solid NH4Cl (s) is introduced to the reaction vessel of 500 mL and the system is allowed to reach equilibrium, calculate for the partial pressure of the ammonia. NH4Cl (s) NH4 (g) + HCl (g) C. 0.0212 atm A. 0.104 atm B. 8.41 atm D. 5.30 atm E. 0.00198 atm 11. What is the Kc of the reaction at the given temperature? A. 2.48 x 10-9 B. 2.35 x 10-4 C. 1.59 x 10-3 D. 5.16 x 10-6 12. Calculate the temperature needed to change the Kp of the reaction to twice of the initial equilibrium constant. The A,H= 176.01 kJ/mol A. 538 K B. 558 K C. 265 K D. 285 K
For items 10-12. The decomposition of NH4Cl (s) at a given temperature of 548 K, the Kp = 0.01072. NH4Cl (s) NH4 (g) + HCl (g) = 10. If 10.00 g of solid NH4Cl (s) is introduced to the reaction vessel of 500 mL and the system is allowed to reach equilibrium, calculate for the partial pressure of the ammonia. NH4Cl (s) NH4 (g) + HCl (g) C. 0.0212 atm A. 0.104 atm B. 8.41 atm D. 5.30 atm E. 0.00198 atm 11. What is the Kc of the reaction at the given temperature? A. 2.48 x 10-9 B. 2.35 x 10-4 C. 1.59 x 10-3 D. 5.16 x 10-6 12. Calculate the temperature needed to change the Kp of the reaction to twice of the initial equilibrium constant. The A,H= 176.01 kJ/mol A. 538 K B. 558 K C. 265 K D. 285 K
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For items 10-12. The decomposition of NH4Cl (s) at a given temperature of 548 K, the Kp = 0.01072.
NH4Cl (s) = NH4 (g) + HCl (g)
10. If 10.00 g of solid NH4Cl (s) is introduced to the reaction vessel of 500 mL and the system is
allowed to reach equilibrium, calculate for the partial pressure of the ammonia.
NH4Cl (s) NH4 (g) + HCl (g)
C. 0.0212 atm
A. 0.104 atm
B. 8.41 atm
D. 5.30 atm
E. 0.00198 atm
11. What is the Kc of the reaction at the given temperature?
A. 2.48 x 10-⁹
B. 2.35 x 10-4
C. 1.59 x 10-3
D. 5.16 x 10-6
12. Calculate the temperature needed to change the Kp of the reaction to twice of the initial
equilibrium constant. The A,H= 176.01 kJ/mol
A. 538 K
B. 558 K
C. 265 K
D. 285 K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8266bef2-0afd-4fb2-93d4-95b483e08cba%2Fe8c50577-71e4-4033-85ba-538d8c206fa8%2Fvnn3u8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For items 10-12. The decomposition of NH4Cl (s) at a given temperature of 548 K, the Kp = 0.01072.
NH4Cl (s) = NH4 (g) + HCl (g)
10. If 10.00 g of solid NH4Cl (s) is introduced to the reaction vessel of 500 mL and the system is
allowed to reach equilibrium, calculate for the partial pressure of the ammonia.
NH4Cl (s) NH4 (g) + HCl (g)
C. 0.0212 atm
A. 0.104 atm
B. 8.41 atm
D. 5.30 atm
E. 0.00198 atm
11. What is the Kc of the reaction at the given temperature?
A. 2.48 x 10-⁹
B. 2.35 x 10-4
C. 1.59 x 10-3
D. 5.16 x 10-6
12. Calculate the temperature needed to change the Kp of the reaction to twice of the initial
equilibrium constant. The A,H= 176.01 kJ/mol
A. 538 K
B. 558 K
C. 265 K
D. 285 K
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