For items 1 to 4: Part of a study conducted at Virginia Tech was designed to measure serum alkalinephosphatase activity levels (in Bessey-Lowry units) in children with seizure disorders who were receivinganticonvulsant therapy under the care of a private physician. Forty-five subjects were found for the study andcategorized into four drug groups:• G-1: Control (not receiving anticonvulsants and having no history of seizure disorders)G-2: PhenobarbitalG-3: CarbamazepineG-4: Other anticonvulsantsFrom blood samples collected from each subject, the serum alkaline phosphatase activity level was determinedand recorded. To test the hypothesis that the average serum alkaline phosphatase activity level is the same forthe four drug groups, an one-way ANOVA F test was conducted. Below is the incomplete ANOVA table:SourceSSdfMSFcritDrug Group139392.83ErrorTotal123541What is the value of test statisticO 5.4687O 5.5958O 1.7381O 1.2718 What would be the appropriate decision and conclusion?O Do not reject the null hypothesis; no sufficient evidence suggesting any difference in phosphate activity levels across thefour drug groupsDo not reject the null hypothesis; phosphate activity level is different across for the four drug groupsO Reject the null hypothesis; phosphate activity level is the same for the four drug groupsO Reject the null hypothesis; phosphate activity level is the same for the four drug groups

Fill the incomplete Anova table Find the value of test statistic and appropriate decision and…

Answered: For items 1 to 4: Part of a study…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Healthy men aged 21 to 35 were randomly assigned to one of two groups: half received 0.82 grams of alcohol per kilogram of body weight; half received a placebo. Participants were then given 30 minutes to read up to 34 pages of Tolstoy’s War and Peace (beginning at chapter 1, with each page containing approximately 22 lines of text). Every two to four minutes participants were prompted to indicate whether they were “zoning out.” The proportion of times participants indicated they were zoning out was recorded for each subject. The table below summarizes data on the proportion of episodes of zoning out (a) What are the two sample standard deviations? (b) What degrees of freedom does the conservative Option 2 use for two-sample t procedures for these samples? (c) Using Option 2, give a 90% confidence interval for the mean difference between the two groups.
A special education teacher did research on whether or not there is a relationship between the number of students in his class and the number incidents of “acting out” behaviors exhibited by the autistic students in the classroom. He collects data for a year and aggregates them by month. He obtained the statistics below, r= -.863 R2=.74 b= -1.212294 a= 131.176598 10.) How does the presence of more students affect the incidents in the class? a) as students are added the incidences increase b) as students are added the incidences decrease c) the number of students does not affect acting out d) the number of students caused more incidents How much of the variability of acting out is explained by the number of students in the class?___________
We are testing whether a particular program of low impact exercise can improve the cholesterol level of stroke patients. We enroll a group of stroke patients in our study, and after six weeks we measure their serum cholesterol level in mmol/L, resulting in the following data: 6.1 9.3 6.3 4 9 5.5 6.3 4.2 4.7 7.8 4.3 7.5 9.1 4.2 6.9 8.1 5.6 9.4 8.3 8.8 7.2 5.7 6.5 3.8 3.8 9 9.4 4.5 8 7 4.5 9.4 6.6 4.1 6.6 9.1 3.9 5.3 (a) Construct a 95% confidence interval. _______< u < ______ From an existing study, we know that the average cholesterol level of all stroke patients is 7 mmol/L. We want to know if the level in our patients is significantly different from this. (b) What is our Test statistic? ______ (c) What is the two-tailed p-value of this result? ______
Healthy men aged 21–35 were randomly assigned to one of two groups: half received 0.82 gram of alcohol per kilogram of body weight; half received a placebo. Participants were then given 30 minutes to read up to 34 pages of Tolstoy’s War and Peace (beginning at Chapter 1, with each page containing approximately 22 lines of text). Every two to four minutes, participants were prompted to indicate whether they were “zoning out.” The proportion of times participants indicated they were zoning out was recorded for each subject. The following table summarizes data on the proportion of episodes of zoning out. Group n S Alcohol 25 0.25 0.05 Placebo 25 0.12 0.03 Do we have evidence to claim that two groups have different means?
Consider the following data on price ($) and the overall score for six stereo headphones tested by a certain magazine. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). Brand Price ($) A B C D E F Ọ Ho Bo=0 Ha: Bo #0 OHO: B₁ ≥ 0 H₂: B₁ <0 O Ho: B₁ * 0 H₂: B₁ = 0 180 ⒸH₁: B₁ = 0 H₂: B₁ 0 150 95 70 70 35 Score 76 69 59 56 40 (a) The estimated regression equation for this data is ý = 21.926421 + 0.320736x, where x = price ($) and y = overall score. Does the t test indicate a significant relationship between price and the overall score? Use a = 0.05. State the null and alternative hypotheses. o Ho Boo Hà Bo=0 24 Find the value of the test statistic. (Round your answer to three decimal places.) 4.558263 Find the p-value. (Round your answer to four decimal places.) p-value = 0.010352 What is your conclusion? O Do not reject Ho. We cannot conclude that the relationship between price ($) and overall score is…
Researchers have shown that cigarette smoking has a deleterious effect on lung function. In their study of the effect of cigarette smoking on the carbon monoxide diffusing capacity (DL) of the lung, Ronald Knudson, W. Kaltenborn and B. Burrows found that current smokers had DL readings significantly lower than either ex-smokers or nonsmokers. The carbon monoxide diffusing capacity for a random sample of current smokers was as follows: 103.768 88.602 73.003 123.086 91.052 92.295 61.675 90.677 84.023 76.014 100.615 88.017 71.210 82.115 89.222 102.754 108.579 73.154 106.755 90.479 Do these data indicate that the mean DL reading for current smokers is lower than 100, the average DL reading for nonsmokers? A. Find the test statistics and interpret the results, a = 0.01? B. Calculate p value and interpret the results. C. Find the confidence interval for a = 0.05.
Have you ever been frustrated because you could not get a container of some sort to release the last bit of its contents? An article reported on an investigation of this issue for various consumer products. Suppose five 6.0 oz tubes of toothpaste of a particular brand are randomly selected and squeezed until no more toothpaste will come out. Then each tube is cut open and the amount remaining is weighed, resulting in the following data: 0.53, 0.64, 0.41, 0.5, 0.35. Does it appear that the true average amount left is less than 10% of the advertised net contents?Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)t= P-value =
C-4) The concentration of active ingredient in a liquid laundry detergent is thought to be affected by the type of catalyst used in the process. Ten observations on concentration are taken with each catalyst, and the data follow: Catalyst 1: 57.9, 66.2. 65.4, 65.4, 65.2. 62.6, 67.6, 63.7, 67.2. 71.0 Catalyst 2: 66.4. 71.7. 70.3. 69.3, 64.8, 69.6, 68.6, 69.4, 65.3, 68.8. Find a 95% confidence interval on the ratio of active concentrations for the two catalysts, and explain it.
3
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A deficiency of the trace element selenium in the diet can negatively impact growth, immunity, muscle and neuromuscular function, and fertility. The introduction of selenium supplements to dairy cows is justified when pastures have low selenium levels. Authors of a research paper supplied the following data on milk selenium concentration (mg/L) for a sample of cows given a selenium supplement (the treatment group) and a control sample given no supplement, both initially and after a 9-day period. Initial Measurement Treatment Control 11.4 9.1 9.6 8.7 10.1 9.7 8.5 10.8 10.2 10.9 10.6 10.6 11.9 10.1 9.9 12.3 10.7 8.8 10.2 10.4 10.3 10.9 11.4 10.4 9.3 11.6 10.6 10.9 10.9 8.3 After 9 Days Treatment Control 138.3 9.2 104 8.9 96.4 8.9 89 10.1 88 9.6 103.8 8.6 147.3 10.4 97.1 12.4 172.6 9.2 146.3 9.5 99 8.4 122.3 8.8 103 12.5 117.8 9.1 121.5 93 (a) Use the given data for the treatment group to determine if…
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