For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H,] = 0.467 M, [I] = 0.467 M, and [HI] = 3.95 M. If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?

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At 500 °C, hydrogen iodide decomposes according to the equation:

\[2 \text{HI}(g) \rightleftharpoons \text{H}_2(g) + \text{I}_2(g)\]

For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium:

\[[\text{H}_2] = 0.467 \, \text{M}, \quad [\text{I}_2] = 0.467 \, \text{M}, \quad \text{and} \quad [\text{HI}] = 3.95 \, \text{M}.\]

If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?

\[
[\text{HI}] = \underline{\hspace{5cm}} \, \text{M}
\]

\[
[\text{H}_2] = \underline{\hspace{5cm}} \, \text{M}
\]
Transcribed Image Text:At 500 °C, hydrogen iodide decomposes according to the equation: \[2 \text{HI}(g) \rightleftharpoons \text{H}_2(g) + \text{I}_2(g)\] For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: \[[\text{H}_2] = 0.467 \, \text{M}, \quad [\text{I}_2] = 0.467 \, \text{M}, \quad \text{and} \quad [\text{HI}] = 3.95 \, \text{M}.\] If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached? \[ [\text{HI}] = \underline{\hspace{5cm}} \, \text{M} \] \[ [\text{H}_2] = \underline{\hspace{5cm}} \, \text{M} \]
The image displays a mathematical or chemical notation represented as:

\[[I_2] = \underline{\hspace{10cm}} \ \text{M}\]

Explanation:
- \([I_2]\) denotes the concentration of iodine, typically expressed in molarity (M).
- The line following the equals sign is a placeholder intended for numerical input, where one might specify the concentration value.
- “M” stands for molarity, a common unit of concentration in chemistry indicating moles per liter.
Transcribed Image Text:The image displays a mathematical or chemical notation represented as: \[[I_2] = \underline{\hspace{10cm}} \ \text{M}\] Explanation: - \([I_2]\) denotes the concentration of iodine, typically expressed in molarity (M). - The line following the equals sign is a placeholder intended for numerical input, where one might specify the concentration value. - “M” stands for molarity, a common unit of concentration in chemistry indicating moles per liter.
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