h= 6.626x10 34 J.s c=2.998x10% m.s1 1 eV = 1.6022x10-19 J 1Å = 1010 m,%3D6.1/2mẹ =9.109x1031 kg, k= 1.3807x10-23 J/K Sº x*e¬ax² dx =-8a216S" sin50 de =-15 For 'H3$Cl molecule, (N1/No) ratio at 300 K is 6.091 x 10². Calculate thewavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

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Answered: For 'H3$Cl molecule, (N¡/No) ratio at…

For 'H3$Cl molecule, (N¡/No) ratio at 300 K is 6.091 x 10² . Calculate the wavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

h= 6.626x10 34 J.s c=2.998x10% m.s1 1 eV = 1.6022x10-19 J 1Å = 1010 m,
%3D
6.
1/2
mẹ =9.109x1031 kg, k= 1.3807x10-23 J/K Sº x*e¬ax² dx =-
8a2
16
S" sin50 de =-
15

For 'H3$Cl molecule, (N1/No) ratio at 300 K is 6.091 x 10². Calculate the
wavenumber ( in cm') for J=2→J=3 transition in the microwave spectrum of the molecule.

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