10. For given data (x₁,y₁), i = 1, 2..., n, the solution of equationsƏcaƏdni=172i=1provides the least squares method fit by[y₁ − (cx₁ +d)]²=0-(A) a parabola (cx + d)²(B) a cubic (cx; + d) ³(C) a straight line cx + d(D) constant functions y₁ = c and y2 = d.[y₁ − (cx₁ +d)]²=0-

Look inside the summation its like summing up square of distances of y to some fixed cx+d.Least…

Answered: For given data (xi,yi), i = 1, 2..., n,…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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7. The equation of a circle can be represented as centered at (3, -1) with radius 5, y = (x - h)? + (y – k)² = r², where (h, k) is the center of the circle and r is its radius. For a circle can be represented as %3D - A) -1t /25 – (x - 3)2 B) -1±/25 + (x – 3)2 C) 1+ /25 – (x – 3)2 | D) 1+/25 + (x – 3)²
Consider the following equations: (a) y = 3x +7 (b) y + y = 0 (c) y/y= 232 (d) = 84x de (e) a2 + y? = 36 (f) a*/" + 4x*y/ = sin (æº) (g) + æ? = 36t For each of the following questions, answer with a list of letters, such as a,c,d. Which of the equations are: differential equations? linear differential equations? first order differential equations? autonomous differential equations?
9. Let y=3x+2 a) typically we write points in this scenario as (x,y), not (y,x), why is that? b) on a horizontal axis, represent 3 things: x=-2, x=4, and Δx=4-(-2). c) on a vertical axis, represent 3 things: y=-4, y=14, and Δy=14-(-4). d) draw a sketch of y=f(x) which includes the points (-2,-4) and (4,14). Mark and label Δx and Δy for those two points on this graph. e) calculate that rate, then write the change equation for x and y f) if the change in x is 2, what is the change in y? g) if the change in y is -12, what is the change in x? h) if we swapped x and y (with x on the vertical axis so x=g(y)), what would the rate be?

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For given data (xi,yi), i = 1, 2..., n, the solution of equations a ac Σlyi - (cx; + d)]² = 0 i=1 od Σlyi - (cx₁ + d)]² = 0 i=1