For example, the code on the left should create a tree on the right:int main () {PrefixTreeNode *root = new PrefixTreeNode () ;root.children [l]children (3]insert (root, "cat"):d..children [14]insert (root,"car");.children [4]insert (root, "dog");ea. wordEnds == trueinsert (root, "do");.children [4].children[17]insert (root, "bee");erinsert (root, "dorm");. wordEnds == truechildren [12]delete root;mwordEnds ==trueFill in the insert method below that inserts a string t to the prefix tree rooted at root.void insert (PrefixTreeNode *root, const string &t) {// Copy this function in answer and add code below this line. The prefix tree is a search tree data structure to store a set of strings. A prefix tree has the following properties:• Each prefix tree has a root indicating the start of each string.• Each path from the root node in the tree corresponds to a prefix of some string.• Each node has a flag to denote if the prefix is actually also a string in the set.For example, suppose we have 4 strings: "cat", "car", "dog", and "do". The corresponding prefix tree should conceptually be as follows, where the shaded nodes indicate the end of a string.rootdaAssume the strings only contain lowercase English letters.The PrefixTreeNode class is given below.class PrefixTreeNodepublic:PrefixTreeNode *children [26]; // the child nodes for 26 lettersbool wordEnds; // indicates the end of a stringPrefixTreeNode ()wordEnds = false;for (int i = 0; i < 26; i++)children [i] = NULL;} ;children is an array of pointers pointing to sub-prefix-trees of the 26 English letters. At each node, children[0] corresponds to the tree for the next letter being 'a', children [1] corresponds to the tree for letter 'b', children [2] corresponds toletter 'c', and so on.wordEnds is the flag indicating if there is a string that ends at the current node.For example, the code on the left should create a tree on the right:

Answered: Image /qna-images/answer/0486b20a-1654-4154-af31-d7c6c48c7f55.jpg

For example, the code on the left should create a tree on the right: int main () { PrefixTreeNode *root = new PrefixTreeNode () : root .children (1] children(3] insert (root, "cat"): b d children [14] insert (root, "car"): .children [4] insert (root, "dog"): e a .wordEnds == true insert (root, "do") : .children [4] children[17) insert (root, "bee"); e t g insert (root, "dorm") : . wordEnds =- .children[12] true delete root: m .wordEnds == true Fill in the insert method below that inserts a string t to the prefix tree rooted at root. void insert (PrefixTreeNode *root, const string &t) { // Copy this function in answer and add code below this line.

For example, the code on the left should create a tree on the right: int main () { PrefixTreeNode root = new PrefixTreeNode () : root .children (1] children(3] insert (root, "cat"): b d children [14] insert (root, "car"): .children [4] insert (root, "dog"): e a .wordEnds == true insert (root, "do") : .children [4] children[17) insert (root, "bee"); e t g insert (root, "dorm") : . wordEnds =- .children[12] true delete root: m .wordEnds == true Fill in the insert method below that inserts a string t to the prefix tree rooted at root. void insert (PrefixTreeNode root, const string &t) { // Copy this function in answer and add code below this line.

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

For example, the code on the left should create a tree on the right:
int main () {
PrefixTreeNode *root = new PrefixTreeNode () ;
root
.children [l]
children (3]
insert (root, "cat"):
d.
.children [14]
insert (root,
"car");
.children [4]
insert (root, "dog");
e
a
. wordEnds == true
insert (root, "do");
.children [4]
.children[17]
insert (root, "bee");
e
r
insert (root, "dorm");
. wordEnds == true
children [12]
delete root;
m
wordEnds ==
true
Fill in the insert method below that inserts a string t to the prefix tree rooted at root.
void insert (PrefixTreeNode *root, const string &t) {
// Copy this function in answer and add code below this line.

The prefix tree is a search tree data structure to store a set of strings. A prefix tree has the following properties:
• Each prefix tree has a root indicating the start of each string.
• Each path from the root node in the tree corresponds to a prefix of some string.
• Each node has a flag to denote if the prefix is actually also a string in the set.
For example, suppose we have 4 strings: "cat", "car", "dog", and "do". The corresponding prefix tree should conceptually be as follows, where the shaded nodes indicate the end of a string.
root
d
a
Assume the strings only contain lowercase English letters.
The PrefixTreeNode class is given below.
class PrefixTreeNode
public:
PrefixTreeNode *children [26]; // the child nodes for 26 letters
bool wordEnds; // indicates the end of a string
PrefixTreeNode ()
wordEnds = false;
for (int i = 0; i < 26; i++)
children [i] = NULL;
} ;
children is an array of pointers pointing to sub-prefix-trees of the 26 English letters. At each node, children[0] corresponds to the tree for the next letter being 'a', children [1] corresponds to the tree for letter 'b', children [2] corresponds to
letter 'c', and so on.
wordEnds is the flag indicating if there is a string that ends at the current node.
For example, the code on the left should create a tree on the right:

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12:34 A cs61a.org Implement add_d_leaves, a function that takes in a Tree instance t and a number v. We define the depth of a node in t to be the number of edges from the root to that node. The depth of root is therefore 0. For each node in the tree, you should add d leaves to it, where d is the depth of the node. Every added leaf should have a label of v. If the node at this depth has existing branches, you should add these leaves to the end of that list of branches. For example, you should be adding 1 leaf with label v to each node at depth 1, 2 leaves to each node at depth 2, and so on. Here is an example of a tree t (shown on the left) and the result after add_d_leaves is applied with v as 5. 3 2 3 2 4 4 5 5 5 Hint: Use a helper function to keep track of the depth! def add_d_leaves(t, v): """Add d leaves containing v to each ng