for each value of V, above and find the percent di V, does the percent error become greater than or

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A full-wave bridge rectifier is constructed using 4 germanium diodes, each with a forward voltage drop of 0.3 V. The rectified waveform
is described by the function vout(0) = V, sin 0 - 2 Vp where 8 = sin1 (2Vp/V,). Use integration to determine the exact average value of
Vout for V, = 1.5, 2, 2.5, 3, 3.5, 4, and 4.5 V (using Excel or Matlab will speed up this process considerably). Then use the estimation
formula (0.636 V, - 2 Vp) to determine the average value for each value of V, above and find the percent difference between the exact
and estimated values for each V, value. At what value of V, does the percent error become greater than or equal to 5%?
OVs = 2 V
OVs - 1.5 V
OVs - 2.5 V
OVs - 3V
Transcribed Image Text:A full-wave bridge rectifier is constructed using 4 germanium diodes, each with a forward voltage drop of 0.3 V. The rectified waveform is described by the function vout(0) = V, sin 0 - 2 Vp where 8 = sin1 (2Vp/V,). Use integration to determine the exact average value of Vout for V, = 1.5, 2, 2.5, 3, 3.5, 4, and 4.5 V (using Excel or Matlab will speed up this process considerably). Then use the estimation formula (0.636 V, - 2 Vp) to determine the average value for each value of V, above and find the percent difference between the exact and estimated values for each V, value. At what value of V, does the percent error become greater than or equal to 5%? OVs = 2 V OVs - 1.5 V OVs - 2.5 V OVs - 3V
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