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True or False
For each statement below, indicate whether you think it is True or False
- For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element
- Binary search can be used on an unsorted array to significantly improve its performance from O(n) to O(1)
- Because the update
algorithm depends on using linear search, its performance is O(1) in the worst case scenario - If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n)
- If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)
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- Q:During each iteration of Quick Sort algorithm, the first element of array is selected as a pivot. The algorithm for Quick Sort is given below. Modify it in such a way that last element of array should be selected as a pivot at each iteration. Also explain the advantages.True or False For each statement below, indicate whether you think it is True or False. If you use binary search on a sorted array, the performance at worst is O(log n) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value Binary search can be used on an unsorted array Inserting elements into a sorted array is O(n) because you have to find the location to add the new element and then shift the remaining elements If the sorted array gets too large, the performance of binary search becomes O(n) For the delete algorithm, after you find the element to delete, you can make the algorithm run faster by replacing it with the last element in the array If you used binary search to…Function PrintArray(integer array(?) dataList) returns nothing integer i for i = 0; i < dataList.size; i = i + 1 dataList[i] = Get next input Put dataList to output Put "_" to output // Your solution goes here. Modify as needed i = 0 Complete the PrintArray function to iterate over each element in dataList. Each iteration should put the element to output. Then, put "_" to output. Ex: If dataList's elements are 2 4 7, then output is: 2_4_7_ Function Main() returns nothing integer array(3) userNums integer i for i = 0; i < userNums.size; i = i + 1 userNums[i] = Get next input PrintArray(userNums)
- Java Program Your program should use 2D arrays to implement simple matrix operations. Your program should do the following: • Read the number of rows and columns of a matrix M1 from the user. Use an input validation loop to make sure the values are greater than 0. • Read the elements of M1 in row major order • Print M1 to the console; make sure you format as a matirx • Repeat the previous steps for a second matrix M2 • Create a matrix M3 that is the transpose of M1 and print it to the console • Check if M1 and M2 can be added (should have the same dimensions). If possible, add M1 and M2 and print the result to the console. Otherwise print an error message. • Extra credit: Multiply M1 and M2 if possible and print to the console. If the matrices cannot be multiplied, print an error message. Implementation requirements: • Use a helper method for reading a positive integer using an input validation loop. • Use a helper method for printing a matrix. Your helper methods should be private and…Code only_Given an unsorted array A of size N that contains only positive integers, find a continuous sub-array that adds to a given number S and return the left and right index(1-based indexing) of that subarray. In case of multiple subarrays, return the subarray indexes which come first on moving from left to right. Note:- You have to return an ArrayList consisting of two elements left and right. In case no such subarray exists return an array consisting of element -1..Select true or false for the statements below. Explain your answers if you like to receive partial credit Select true or false for the statements below. Explain your answers if you like to receive partial credit Which of the following is true about searching elements in an unordered array? With the data is unsorted, search is O(n) because if the element you are looking for is not there, you have to check every element in the array If you start at the end of the array and traverse to index 0, search improves to O(log n) because you only have to look at half of the array If you get lucky with checking the first element and find it immediately, then the worst case performance of search improves to O(n^2) Which of the following is true about searching elements in an ordered array? You cannot use binary search on an ordered array so the performance is O(n) If there are no holes in the array and the elements are all next to each other, then the performance for search improves to…
- : In searching an element in an array, linear search can be used, even though simple to implement, but not efficient, with only O(n) time complexity. Assuming the array is already in sorted order, modify the search function below, using a better algorithm, so the average time complexity for the search function is O(log n). include <iostream> using namespace std; int search(int al), int s, int v) { 1/ Modify below codes. for (int i = 0; i <s; i++) { if (a[i] = v) return i; return -1; int main() { int intArray:10] = { 5, 7, 8, 9, 10, 12, 13, 15, 20, 34); // Search for element '12' in 10-elements integer array. cout << search(intArray, 10, 12); // '5' will be printed out. // Search for element '35' in 10-elements integer array. cout << search(intArray, 10, 35); // '-1' will be printed out. // Index '-l' means that the element is not found. return 0;List all the steps used to search for 18 in the sequence 1, 2, 4, 8, 10, 12, 18, 20, 22. Be sure to show EVERY step. A. linear search B. binary search Use the following array and indices in your answer: Array: 1 2 4 8 10 12 18 20 22 Index: 1 2 3 4 5 6 7 8 9Select true or false for the statements below. Explain your answers if you like to receive partial credit1) Which of the following is true about searching elements in an unordered array?a. With the data is unsorted, search is O(n) because if the element you arelooking for is not there, you have to check every element in the arrayb. If you start at the end of the array and traverse to index 0, search improvesto O(log n) because you only have to look at half of the arrayc. If you get lucky with checking the first element and find it immediately, thenthe worst case performance of search improves to O(n^2)
- value You are given 4 items as {value, weightpairs in this format {{20, 5}, {60, 20}, {25, 10}, {X, 25}}You can assume that the array is sorted based on the ratio. The weight capacity of knapsack is 50. The item no. 4 (whose weightis 25 ) is taken fractionally to fill upto the knapsack capacity. That fraction is represented in format. What is the lowest possible value of b? For the question above, assume the total value stored in the knapsack is 135 after you have filled upto the knapsack capacity. What is the value of X(in other words, the valueof the item no. 4) ? Give your answer to at least two decimal places.Given an array of 5-DWORD elements with values: 10,3,9,8,2 copy the values from last to first to a second 5-DWORD-element array Note 1: Use the loop as well as push and pop instructions Note 2: Use the LENGTHOF operator to get the number of elements of the array Note 3: Your algorithm should work for any array irrespective of its size with minimal mod- ificationsConsider the algorithm for insertion sort shown below. The input to this algorithm is an array A. You must assume that indexing begins at 1.