For each of the three heat pumps described, state whether it violates the First Law of Thermodynamics, the Second Law of Thermodynamics or neither. All three have a hot reservoir temperature of 400K and a cold reservoir temperature of 300K . 100J of work are done to the system. 200J of heat are pulled from the cold reservoir. 300J of heat are dumped into the hot reservoir. b. 50J of work are done to the system. 250J of heat are pulled from the cold reservoir. 3001 f hoot

Elements Of Electromagnetics
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For each of the three heat pumps described, state whether it violates the First Law of
Thermodynamics, the Second Law of Thermodynamics or neither. All three have a hot reservoir
temperature of 400K and a cold reservoir temperature of 300K.
a. 100J of work are done to the system. 200J of heat are pulled from the cold reservoir.
300J of heat are dumped into the hot reservoir.
b. 50J of work are done to the system. 250J of heat are pulled from the cold reservoir.
300J of heat are dumped into the hot reservoir.
c. 100J of work are done to the system. 100J of heat are pulled from the cold reservoir.
300J of heat are dumped into the hot reservoir.
Transcribed Image Text:For each of the three heat pumps described, state whether it violates the First Law of Thermodynamics, the Second Law of Thermodynamics or neither. All three have a hot reservoir temperature of 400K and a cold reservoir temperature of 300K. a. 100J of work are done to the system. 200J of heat are pulled from the cold reservoir. 300J of heat are dumped into the hot reservoir. b. 50J of work are done to the system. 250J of heat are pulled from the cold reservoir. 300J of heat are dumped into the hot reservoir. c. 100J of work are done to the system. 100J of heat are pulled from the cold reservoir. 300J of heat are dumped into the hot reservoir.
Expert Solution
Step 1

Given Data:

  • The temperature of the cold reservoir is TL=300 K.
  • The temperature of the hot reservoir is TH=400 K.

The highest COP of the heat pump possible can be determined as,

COPrev=THTH-TL=400 K400 K-300 K=4.

 

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