For each of the following reactions, indicate if the equilibrium mixture contains mostly products, mostly reactants, or both reactants and products: 2H,0(g),* 2H2(g) + 02(g), K-=4x10-48 O2 (g) + 2SO, (g) 250;(g), K-=1.2x10° 250;(g), K.=1.2x10°

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**Determining Equilibrium Composition in Chemical Reactions**

For each of the following reactions, indicate if the equilibrium mixture contains mostly products, mostly reactants, or both reactants and products:

1. **Reaction:** 
   \[
   2 \text{H}_2\text{O} (g) \rightleftharpoons 2 \text{H}_2 (g) + \text{O}_2 (g), \quad K_c = 4 \times 10^{-48}
   \]

   - **Interpretation:** The equilibrium constant \(K_c\) is extremely small (\(4 \times 10^{-48}\)), indicating that at equilibrium, the concentration of reactants (\(\text{H}_2\text{O}\)) is much higher than the concentration of products (\(\text{H}_2\) and \(\text{O}_2\)). Therefore, the equilibrium mixture contains mostly reactants.

2. **Reaction:**
   \[
   \text{O}_2 (g) + 2 \text{SO}_2 (g) \rightleftharpoons 2 \text{SO}_3 (g), \quad K_c = 1.2 \times 10^9
   \]

   - **Interpretation:** The equilibrium constant \(K_c\) is very large (\(1.2 \times 10^9\)), indicating that at equilibrium, the concentration of products (\(\text{SO}_3\)) is much higher than the concentration of reactants (\(\text{O}_2\) and \(\text{SO}_2\)). Therefore, the equilibrium mixture contains mostly products.

### Understanding Equilibrium Constants (\(K_c\))

- **Small \(K_c\) (< 1):** The system at equilibrium contains more reactants than products.
- **Large \(K_c\) (> 1):** The system at equilibrium contains more products than reactants.
- **\(K_c\) ≈ 1:** Significant concentrations of both reactants and products are present at equilibrium.

These values help chemists predict the direction in which a reaction will proceed to reach equilibrium.
Transcribed Image Text:**Determining Equilibrium Composition in Chemical Reactions** For each of the following reactions, indicate if the equilibrium mixture contains mostly products, mostly reactants, or both reactants and products: 1. **Reaction:** \[ 2 \text{H}_2\text{O} (g) \rightleftharpoons 2 \text{H}_2 (g) + \text{O}_2 (g), \quad K_c = 4 \times 10^{-48} \] - **Interpretation:** The equilibrium constant \(K_c\) is extremely small (\(4 \times 10^{-48}\)), indicating that at equilibrium, the concentration of reactants (\(\text{H}_2\text{O}\)) is much higher than the concentration of products (\(\text{H}_2\) and \(\text{O}_2\)). Therefore, the equilibrium mixture contains mostly reactants. 2. **Reaction:** \[ \text{O}_2 (g) + 2 \text{SO}_2 (g) \rightleftharpoons 2 \text{SO}_3 (g), \quad K_c = 1.2 \times 10^9 \] - **Interpretation:** The equilibrium constant \(K_c\) is very large (\(1.2 \times 10^9\)), indicating that at equilibrium, the concentration of products (\(\text{SO}_3\)) is much higher than the concentration of reactants (\(\text{O}_2\) and \(\text{SO}_2\)). Therefore, the equilibrium mixture contains mostly products. ### Understanding Equilibrium Constants (\(K_c\)) - **Small \(K_c\) (< 1):** The system at equilibrium contains more reactants than products. - **Large \(K_c\) (> 1):** The system at equilibrium contains more products than reactants. - **\(K_c\) ≈ 1:** Significant concentrations of both reactants and products are present at equilibrium. These values help chemists predict the direction in which a reaction will proceed to reach equilibrium.
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