For each of the following, complete the steps listed below. **Identify and write each step with the appropriate corresponding number.**1. Write the claim and the null and the alternate hypotheses with proper notation. 2. Identify the level of significance. 3. Draw a distribution to represent it and identify the critical value. 4. Write the inequality that identifies the rejection area(s). 5. **USE YOUR CALCULATOR** to find the t-test statistic and the p-value. 6. Make a decision about your test. 7. Write a sentence describing your decision about the claim.---**Problem #1**A physician claims that an experimental medication *increases* an individual's heart rate. Twelve test subjects are randomly selected and the heart rate of each is measured. The subjects are then injected with the medication and, after one hour, the heart rate of each is measured again. The results are listed below. Assuming the heart rates are normally distributed, is there enough evidence to support the physician’s claim at \(\alpha = 0.05\)?| | | | | | | | | | | | ||-------|---|---|---|---|---|---|---|---|---|---|---|| Before | 72 | 81 | 76 | 74 | 75 | 81 | 68 | 75 | 78 | 76 | 74 | 77 || After | 73 | 80 | 79 | 76 | 76 | 82 | 74 | 77 | 75 | 75 | 76 | 80 |

The question is about paired t test Given : Randomly selected no. of subjects ( n ) = 12 To find : Test the given claim1 ) Claim : Exp. medication increases an individual's heart rate Null and alt. hypo : H0 : μd ≥ 0Ha : μd < 0Where,d = Before - After 2 ) Level of signif. ( α ) = 0.05 3 ) Critical value : df = n - 1 = 12 - 1 = 11 Since alt. hypo. has < sign, so it is left tailed test tcritical = tα,df = t0.05,11 Using excel command, =T.INV ( α, df ) So, tcritical = -1.79588 Shaded area indicates rejection region 4 ) Rejection region : If tstat ≤ -1.79588 then it would go under rejection region and implies rejecting the null hypo. 5 ) Using TI-84 Plus calculator : i ) Go to STAT -- > Edit -- > 1. Edit ii ) Enter the values of " d " into list L1 iii ) Go to STAT -- > TESTS -- > 2. T - Test μ0 : 0 List : L1 Freq. : 1 μ : select " < μ0" Press on calculate It would provide output as Test stat ( tstat ) = -2 p value ( p ) = 0.035402 6 ) Decision rule : If p value < level of signif. ( α ) then reject H0 otherwise fail to reject H0 Here, p value < α Hence, reject H0 7 ) Conclusion : There is suffi. evid. to support the claim that exp. medication increases an individual's heart rate