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For each iteration tableau, clearly mark: U₁, Vj values, C₁j + or negative values, the loop, the entering BV, the leaving BV. At the end of each iteration, also write out clearly what the new BF solution, and the new obiection value.

For each iteration tableau, clearly mark: U₁, Vj values, C₁j + or negative values, the loop, the entering BV, the leaving BV. At the end of each iteration, also write out clearly what the new BF solution, and the new obiection value.

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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### Transportation Problem Consider the transportation problem having the following parameter table: | | Destination 1 | Destination 2 | Destination 3 | Supply | |---------|---------------|---------------|---------------|--------| | Source 1 | 3 | 2.7 | 0 | 5 | | Source 2 | 2.9 | 2.8 | 0 | 4 | | Demand | 3 | 4 | 2 | | ### Initial Basic Feasible (BF) Solution The initial BF solution is given by: - \(x_{11} = 3\) - \(x_{12} = 2\) - \(x_{22} = 2\) - \(x_{23} = 2\) Interactively apply the transportation simplex method to obtain an optimal solution. ### Initial Transportation Simplex Tableau | | Destination 1 | Destination 2 | Destination 3 | Supply | \(u_i\) | |-------------|---------------|---------------|---------------|--------|---------| | **Source 1** | 3 | 2.7 | 0 | 5 | | | | | (3) | (2) | | | | **Source 2** | 2.9 | 2.8 | 0 | 4 | | | | | | (2) | | | | **Demand** | 3 | 4 | 2 | | | | \(v_j\) | | | | | | ### Iterative Process For each iteration tableau, clearly mark: - \(u_i, v_j\) values - \(\bar{c}_{ij}\) (positive or negative values) - The loop - Entering Basic Variable (BV) - Leaving Basic Variable (BV) At the end of each iteration, also write out clearly what the new BF solution is and the new objective value.
Transcribed Image Text:### Transportation Problem Consider the transportation problem having the following parameter table: | | Destination 1 | Destination 2 | Destination 3 | Supply | |---------|---------------|---------------|---------------|--------| | Source 1 | 3 | 2.7 | 0 | 5 | | Source 2 | 2.9 | 2.8 | 0 | 4 | | Demand | 3 | 4 | 2 | | ### Initial Basic Feasible (BF) Solution The initial BF solution is given by: - \(x_{11} = 3\) - \(x_{12} = 2\) - \(x_{22} = 2\) - \(x_{23} = 2\) Interactively apply the transportation simplex method to obtain an optimal solution. ### Initial Transportation Simplex Tableau | | Destination 1 | Destination 2 | Destination 3 | Supply | \(u_i\) | |-------------|---------------|---------------|---------------|--------|---------| | **Source 1** | 3 | 2.7 | 0 | 5 | | | | | (3) | (2) | | | | **Source 2** | 2.9 | 2.8 | 0 | 4 | | | | | | (2) | | | | **Demand** | 3 | 4 | 2 | | | | \(v_j\) | | | | | | ### Iterative Process For each iteration tableau, clearly mark: - \(u_i, v_j\) values - \(\bar{c}_{ij}\) (positive or negative values) - The loop - Entering Basic Variable (BV) - Leaving Basic Variable (BV) At the end of each iteration, also write out clearly what the new BF solution is and the new objective value.
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