For cross 2: Total (N) = 583 4 = ר Expected (E) frequency = Total/n = 583/4 = 145.75 %3D %3D Observed (0) Expected (E) (0-E)^2/E Phenotypes Red Eyes /Normal wings White eyes /Normal wings Red eyes/vertical wings White eyes/Vertical wings Total (N) (0-E)^2 248 145.75 10455.0625 71.7328 234 145.75 7788.0625 53.4344 57 145.75 7876.5625 54.0416 44 145.75 10353.0625 71.0330 583 Chi-square test statistic (x') = 250.2419 Chi-square test statistic (x²) = 250.2419 %3D

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 31PPS
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Give a brief analysis on the following chi-square for cross 2(white eyes vestigial wings female × wild type male) ( write a paragraph or more)

For cross 2:
Total (N) = 583
n = 4
Expected (E) frequency
= Total/n = 583/4 = 145.75
Observed (O)
Expected (E)
(0-E)^2
(0-E)^2/E
Phenotypes
Red Eyes /Normal wings
White eyes /Normal wings
Red eyes/vertical wings
White eyes/Vertical wings
Total (N)
248
145.75
10455.0625
71.7328
234
145.75
7788.0625
53.4344
57
145.75
7876.5625
54.0416
44
145.75
10353.0625
71.0330
583
Chi-square test statistic (x³) =
250.2419
Chi-square test statistic (x?) = 250.2419
Transcribed Image Text:For cross 2: Total (N) = 583 n = 4 Expected (E) frequency = Total/n = 583/4 = 145.75 Observed (O) Expected (E) (0-E)^2 (0-E)^2/E Phenotypes Red Eyes /Normal wings White eyes /Normal wings Red eyes/vertical wings White eyes/Vertical wings Total (N) 248 145.75 10455.0625 71.7328 234 145.75 7788.0625 53.4344 57 145.75 7876.5625 54.0416 44 145.75 10353.0625 71.0330 583 Chi-square test statistic (x³) = 250.2419 Chi-square test statistic (x?) = 250.2419
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