For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power dissipated in the load, the power drawn by the supply, the dissipated power at each transistor, and the conversion efficiency? Hint: Po ac= η = VLp² 2RL R= Po ac Pi dc _vcc-VQ1 Ißp Pi dc = ² x TL VLP RL ILP= VPL RL IDQ= ·X VCC Vcc-(VBE1+VBE2)-VEE R+R P2Q= Pi dc - Po ac VQ1=VLP+VBE PQ=P2Q Bp=1LP
For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power dissipated in the load, the power drawn by the supply, the dissipated power at each transistor, and the conversion efficiency? Hint: Po ac= η = VLp² 2RL R= Po ac Pi dc _vcc-VQ1 Ißp Pi dc = ² x TL VLP RL ILP= VPL RL IDQ= ·X VCC Vcc-(VBE1+VBE2)-VEE R+R P2Q= Pi dc - Po ac VQ1=VLP+VBE PQ=P2Q Bp=1LP
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load
resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power
dissipated in the load, the power drawn by the supply, the dissipated power at each transistor,
and the conversion efficiency?
Hint:
Po ac=
η =
VLp²
2RL
R=
Po ac
Pi dc
vcc-VQ1
Ißp
Pi dc =
VLP
RL
ILP=
TL
IDQ=
VPL
RL
X vcc
Vcc-(VBE1+VBE2)-VEE
R+R
P2Q= Pi dc Po ac
VQ1=VLP+VBE
PQ=P2Q
ILP](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1d24718-1ec0-48c4-b1b9-a99e3fd4f8f7%2F2b5f7ff0-cfc6-444f-ad71-77b169b0316c%2Fkt2mlqm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load
resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power
dissipated in the load, the power drawn by the supply, the dissipated power at each transistor,
and the conversion efficiency?
Hint:
Po ac=
η =
VLp²
2RL
R=
Po ac
Pi dc
vcc-VQ1
Ißp
Pi dc =
VLP
RL
ILP=
TL
IDQ=
VPL
RL
X vcc
Vcc-(VBE1+VBE2)-VEE
R+R
P2Q= Pi dc Po ac
VQ1=VLP+VBE
PQ=P2Q
ILP
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