Need help writing this code based off of the last checkpoints code: Last code in image.Checkpoint BFor Checkpoint B you will extend Checkpoint A to do the following:Prompts the user for an additional parameter: the bound on the timescale n of the simulationIf a user inputs a negative timescale, the program should immediately print an error message and exit.The program will calculate k,u for every time i<n and output these populations at each stepIf the population grows negative, treat it as population that has become zero. 1. Prompts the user for an additional parameter: the bound on the timescale of the simulation• If a user inputs a negative timescale, the program should immediately print an error message and exit.2. The program will calculate ki, u for every time in and output these populations at each step• If the population grows negative, treat it as population that has become zero.Hint: your program will need a for-loop. Complete this checkpoint after we have introduced for-loops in class.Sample OutputSample input/output behavior for the checkpoint are provided below. Your program's spacing, spelling, capitalization, and punctuation willneed to match the sample output EXACTLY for this project.Ex 1 Sample Input/OutputGiven inputs a, B, 7, 8, ko, uo, nas:1.5.001.052.5100210The program outputs==> Bull Kelp and Purple Urchin Population Simulator <==Model ParametersKelp growth rate:Kelp death rate:Urchin birth rate:Urchin death rate:---Initial PopulationKelp population (in thousands) at t = 0:Urchin population (in thousands) at t = 0:------Simulation------Timescale:Time t = 0: 100.000k kelp, 2.000k urchinsTime t = 1: 249.800k kelp, 7.000k urchinsTime t = 2: 622.751k kelp, 76.930k urchinsTime t = 3:Time t = 4:Time t = 5:4351723217220.qx371508.970k kelp, 2280.018k urchins331.946k kelp, 168603.957k urchins0.000k kelp, 2545463.659k urchins0.000k kelp, 0.000k urchinsTime t = 6:Time t = 7:0.000k kelp, 0.000k urchinsTime t = 8:0.000k kelp, 0.000k urchinsTime t = 9: 0.000k kelp, 0.000k urchinsTime t = 10: 0.000k kelp, 0.000k urchins 1 def main():print("==> Bull Kelp and Purple Urchin Population Simulator <==\n")print("--- Model Parameters ---")4234 in 89567 a2 = float (input("Kelp death rate: \n"))101112131415161718192021222324252627282930# Get the parameters from the useral = float(input ("Kelp growth rate: \n"))313233343536373839a3 = float (input ("Urchin birth rate: \n"))a4 = float (input ("Urchin death rate: \n"))if al < 0:print("Error: cannot have a negative growth rate")returnif a3 < 0:print("Error: cannot have a negative birth rate")return# Check for negative values and exit if any is foundif a2 <0 or a4 < 0:print("Error: cannot have a negative death rate")returnmain.pyprint("\n-Initial Population ---")# Get the initial population values from the userk1 float (input ("Kelp population (in thousands) at t = 0: \n"))=k2 = float (input("Urchin population (in thousands) at t = 0: \n"))# Treat negative populations as zeroif k1 < 0:k1 = 0if k2 < 0:k2 = eprint("\n Simulation ---")print("Time t = 0: {:.3f}k kelp, {:.3f}k urchins". format (k1, k2))# Calculate the populations at t=1f1 = k1+k1 * a1 - k1 a2 * k2f2 = k2 + k2 a3 k1- k2 * a440414243444546474849 if name50 main()# Treat negative populations as zeroif f1 < 0:f1 = 0if f2 < 0:f2 = 0print("Time t = 1: {:.3f}k kelp, {:.3f}k urchins".format(f1, f2))== _main__":Load default template...

We have to update the python code to implement this: Prompts the user for an additional parameter:…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Checkpoint B

For Checkpoint B you will extend Checkpoint A to do the following:

Prompts the user for an additional parameter: the bound on the timescale n of the simulation
- If a user inputs a negative timescale, the program should immediately print an error message and exit.
The program will calculate k,u for every time i<n and output these populations at each step
- If the population grows negative, treat it as population that has become zero.

1. Prompts the user for an additional parameter: the bound on the timescale of the simulation
• If a user inputs a negative timescale, the program should immediately print an error message and exit.
2. The program will calculate ki, u for every time in and output these populations at each step
• If the population grows negative, treat it as population that has become zero.
Hint: your program will need a for-loop. Complete this checkpoint after we have introduced for-loops in class.
Sample Output
Sample input/output behavior for the checkpoint are provided below. Your program's spacing, spelling, capitalization, and punctuation will
need to match the sample output EXACTLY for this project.
Ex 1 Sample Input/Output
Given inputs a, B, 7, 8, ko, uo, nas:
1.5
.001
.05
2.5
100
2
10
The program outputs
==> Bull Kelp and Purple Urchin Population Simulator <==
Model Parameters
Kelp growth rate:
Kelp death rate:
Urchin birth rate:
Urchin death rate:
---
Initial Population
Kelp population (in thousands) at t = 0:
Urchin population (in thousands) at t = 0:
---
---
Simulation
---
---
Timescale:
Time t = 0: 100.000k kelp, 2.000k urchins
Time t = 1: 249.800k kelp, 7.000k urchins
Time t = 2: 622.751k kelp, 76.930k urchins
Time t = 3:
Time t = 4:
Time t = 5:
4351723217220.qx37
1508.970k kelp, 2280.018k urchins
331.946k kelp, 168603.957k urchins
0.000k kelp, 2545463.659k urchins
0.000k kelp, 0.000k urchins
Time t = 6:
Time t = 7:
0.000k kelp, 0.000k urchins
Time t = 8:
0.000k kelp, 0.000k urchins
Time t = 9: 0.000k kelp, 0.000k urchins
Time t = 10: 0.000k kelp, 0.000k urchins

1 def main():
print("==> Bull Kelp and Purple Urchin Population Simulator <==\n")
print("--- Model Parameters ---")
4234 in 89
5
6
7 a2 = float (input("Kelp death rate: \n"))
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
# Get the parameters from the user
al = float(input ("Kelp growth rate: \n"))
31
32
33
34
35
36
37
38
39
a3 = float (input ("Urchin birth rate: \n"))
a4 = float (input ("Urchin death rate: \n"))
if al < 0:
print("Error: cannot have a negative growth rate")
return
if a3 < 0:
print("Error: cannot have a negative birth rate")
return
# Check for negative values and exit if any is found
if a2 <0 or a4 < 0:
print("Error: cannot have a negative death rate")
return
main.py
print("\n-Initial Population ---")
# Get the initial population values from the user
k1 float (input ("Kelp population (in thousands) at t = 0: \n"))
=
k2 = float (input("Urchin population (in thousands) at t = 0: \n"))
# Treat negative populations as zero
if k1 < 0:
k1 = 0
if k2 < 0:
k2 = e
print("\n Simulation ---")
print("Time t = 0: {:.3f}k kelp, {:.3f}k urchins". format (k1, k2))
# Calculate the populations at t=1
f1 = k1+k1 * a1 - k1 a2 * k2
f2 = k2 + k2 a3 k1- k2 * a4
40
41
42
43
44
45
46
47
48
49 if name
50 main()
# Treat negative populations as zero
if f1 < 0:
f1 = 0
if f2 < 0:
f2 = 0
print("Time t = 1: {:.3f}k kelp, {:.3f}k urchins".format(f1, f2))
== _main__":
Load default template...

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions