For cases where [A] exactly doubles: •if the rate does not change, the order for A is 0. •if the rate doubles, then the order for A is 1. • if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: Freactant}, rder [reactant], ratej ratez What is the reaction order with respect to A? [A], mol/L (B], mol/L rate, mol/(L-min) Trial 1 0.873 0.991 0.539 Trial 2 1.75 0.991 0.539 Trial 3 0.873 1.98 1.08 Trial 4 0.876 0.485 0.264 Rate = k[AJorderAB]orderB
For cases where [A] exactly doubles: •if the rate does not change, the order for A is 0. •if the rate doubles, then the order for A is 1. • if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: Freactant}, rder [reactant], ratej ratez What is the reaction order with respect to A? [A], mol/L (B], mol/L rate, mol/(L-min) Trial 1 0.873 0.991 0.539 Trial 2 1.75 0.991 0.539 Trial 3 0.873 1.98 1.08 Trial 4 0.876 0.485 0.264 Rate = k[AJorderAB]orderB
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For cases where [A] exactly doubles:
• if the rate does not change, the order for A is 0.
• if the rate doubles, then the order for A is 1
• if the rate quadruples, the order for A is 2.
For more complex cases, use the general equation:
, [reactant], order
[reactant],
ratei
%3D
rate2
What is the reaction order with respect to A?
[A], mol/L [B], mol/L rate, mol/(L-min)
Trial 1 0.873
0.991
0.539
Trial 2 1.75
0.991
0.539
Trial 3 0.873
1.98
1.08
Trial 4 0.876
0.485
0.264
Rate = k[A]°rderAB]orderB](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa11fcfc-11f7-448e-9db2-5b5a3dd5c606%2F13d370cc-6b89-4d34-beb4-53d84851da6e%2Fkvgxxi8_processed.png&w=3840&q=75)
Transcribed Image Text:For cases where [A] exactly doubles:
• if the rate does not change, the order for A is 0.
• if the rate doubles, then the order for A is 1
• if the rate quadruples, the order for A is 2.
For more complex cases, use the general equation:
, [reactant], order
[reactant],
ratei
%3D
rate2
What is the reaction order with respect to A?
[A], mol/L [B], mol/L rate, mol/(L-min)
Trial 1 0.873
0.991
0.539
Trial 2 1.75
0.991
0.539
Trial 3 0.873
1.98
1.08
Trial 4 0.876
0.485
0.264
Rate = k[A]°rderAB]orderB
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