For an object doing constant acceleration motion in the xy plane, the velocity has been measured at two instants of time as follows: • at time t = 3 s, the velocity is 4 m/s along the negative x direction, • at time t = 7 s, the velocity is 4 m/s along the negative y direction. Note: You will be asked to enter two vector quantities into the boxes below. To enter a vector in unit vector notation such as, 2i +3j m/s, code it as follows: (2*ihat+3*jhat)*m/s^2. (a) Find the acceleration a of the object. a = (b) Find the displacement during the time interval between the two measurements. AT

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For an object doing constant acceleration motion in the xy plane, the velocity has been measured at two instants of time as follows:
• at time t = 3 s, the velocity is
• at time t = 7 s, the velocity is 4 m/s along the negative y direction.
m/s along the negative x direction,
Note: You will be asked to enter two vector quantities into the boxes below. To enter a vector in unit vector notation such as, 2i + 3j m/s, code it as
follows: (2*ihat+3*jhat)*m/s^2.
(a) Find the acceleration a of the object.
a =
(b) Find the displacement during the time interval between the two measurements.
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Transcribed Image Text:For an object doing constant acceleration motion in the xy plane, the velocity has been measured at two instants of time as follows: • at time t = 3 s, the velocity is • at time t = 7 s, the velocity is 4 m/s along the negative y direction. m/s along the negative x direction, Note: You will be asked to enter two vector quantities into the boxes below. To enter a vector in unit vector notation such as, 2i + 3j m/s, code it as follows: (2*ihat+3*jhat)*m/s^2. (a) Find the acceleration a of the object. a = (b) Find the displacement during the time interval between the two measurements. AT Check
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