Find the sum, the resultant and the direction of the vectors by using a scale drawing: 10m/s = 1cm. 1 V₁ = (60m/s at 90°) + V₂ = (80m/s at 0°) 2 V3 = (70m/s at 180°) + V₁ = (50m/s at90°) 3 Vs = (77m/s at 45°) + V6 = (59m/s at 0°) 4 V₁ = (63m/s at 90°) + Vs = (48m/s at 60°) • 5 V, = (89m/s at 30°) + V₁0 (73m/s at 300°) 6 V₁1 (100m/s at 60°) + V₁2 = (50m/s at 360°) ● ●
Find the sum, the resultant and the direction of the vectors by using a scale drawing: 10m/s = 1cm. 1 V₁ = (60m/s at 90°) + V₂ = (80m/s at 0°) 2 V3 = (70m/s at 180°) + V₁ = (50m/s at90°) 3 Vs = (77m/s at 45°) + V6 = (59m/s at 0°) 4 V₁ = (63m/s at 90°) + Vs = (48m/s at 60°) • 5 V, = (89m/s at 30°) + V₁0 (73m/s at 300°) 6 V₁1 (100m/s at 60°) + V₁2 = (50m/s at 360°) ● ●
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![●
Find the sum, the resultant and the
direction of the vectors by using a
scale drawing: 10m/s = 1cm.
•
●
CHAPT. 3 VECTORS
LAB #4
1 V₁ = (60m/s at 90°) + V₂ = (80m/s at 0°)
2 V3 = (70m/s at 180°) + V₁ = (50m/s at90°)
3 Vs = (77m/s at 45°) + V6 = (59m/s at 0°)
4 V₁ = (63m/s at 90°) + V8 = (48m/s at 60°)
5 V₂ = (89m/s at 30°) + V₁0 = (73m/s at 300°)
6 V₁₁ (100m/s at 60°) + V₁2 = (50m/s at 360°)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F52fad7f9-097d-4ed4-a9b8-ba0b37335f42%2F84a6a53f-7096-433e-9cdb-c0eed8dcd1c3%2Fep1xjsg_processed.png&w=3840&q=75)
Transcribed Image Text:●
Find the sum, the resultant and the
direction of the vectors by using a
scale drawing: 10m/s = 1cm.
•
●
CHAPT. 3 VECTORS
LAB #4
1 V₁ = (60m/s at 90°) + V₂ = (80m/s at 0°)
2 V3 = (70m/s at 180°) + V₁ = (50m/s at90°)
3 Vs = (77m/s at 45°) + V6 = (59m/s at 0°)
4 V₁ = (63m/s at 90°) + V8 = (48m/s at 60°)
5 V₂ = (89m/s at 30°) + V₁0 = (73m/s at 300°)
6 V₁₁ (100m/s at 60°) + V₁2 = (50m/s at 360°)
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