For an invertible matrix A, prove that A and A have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A¹? Letting x be an eigenvector of A gives Ax = λx for a corresponding eigenvalue λ. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = λx Ax = λx Ax = λx Ax = λx A/(Ax) = A/(2x) Ax/A = 2x/A A-¹AX = A-¹2x AXA-¹ = 2XA-1 0044 O(A/A)X = (A/2)x O (A/A)X = 2x4-1 OxAA-1 = 24-¹x Ix = 2A-¹x Ix = (A/2)x Ix = 2xA-1 XI = 2A-¹x x = 2A-¹x x = 2A-¹x x = 2x4-1 x = 2A-¹x A-¹x = 1x A-¹x = 1x 2 A-¹x = 1x * 2 A-¹x = 1x λ This shows that --Select--- is an eigenvector of A-1 with eigenvalue ---Select---
For an invertible matrix A, prove that A and A have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A¹? Letting x be an eigenvector of A gives Ax = λx for a corresponding eigenvalue λ. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = λx Ax = λx Ax = λx Ax = λx A/(Ax) = A/(2x) Ax/A = 2x/A A-¹AX = A-¹2x AXA-¹ = 2XA-1 0044 O(A/A)X = (A/2)x O (A/A)X = 2x4-1 OxAA-1 = 24-¹x Ix = 2A-¹x Ix = (A/2)x Ix = 2xA-1 XI = 2A-¹x x = 2A-¹x x = 2A-¹x x = 2x4-1 x = 2A-¹x A-¹x = 1x A-¹x = 1x 2 A-¹x = 1x * 2 A-¹x = 1x λ This shows that --Select--- is an eigenvector of A-1 with eigenvalue ---Select---
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 41EQ
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![For an invertible matrix A, prove that A and A¯ have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A¹?
Letting x be an eigenvector of A gives Ax = λx for a corresponding eigenvalue λ. Using matrix operations and the properties of inverse matrices gives which of the following?
Ax = 2x
Ax = λx
Ax = λx
Ax = 2x
A/(AX) = A/(2x)
AX/A = 2x/A
A-¹AX = A-¹2x
O(A/A)X = (A/2)x
9094
(A/A)X = 2x4-1
Ix = 2A-¹x
Ix = (A/2)x
AXA-1 = 2xA-1
= 2A-¹x
XI = 2A-¹x
OX44-1
IX = 2XA-1
x = 2A-¹x
x = 2A-¹x
x = 2x4-1
x = 2A-¹x
A ¹x = ¹x
A¹x = 1x
2
A¹x = 1x
A-¹x = ¹x
2
This shows that ---Select--- is an eigenvector of A¹ with eigenvalue ---Select---](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56c1d2cf-e8ec-4520-bbe0-3cf55efdd803%2F5e543991-620e-415b-8364-e53861d2a948%2Fbyjr1ci_processed.png&w=3840&q=75)
Transcribed Image Text:For an invertible matrix A, prove that A and A¯ have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A¹?
Letting x be an eigenvector of A gives Ax = λx for a corresponding eigenvalue λ. Using matrix operations and the properties of inverse matrices gives which of the following?
Ax = 2x
Ax = λx
Ax = λx
Ax = 2x
A/(AX) = A/(2x)
AX/A = 2x/A
A-¹AX = A-¹2x
O(A/A)X = (A/2)x
9094
(A/A)X = 2x4-1
Ix = 2A-¹x
Ix = (A/2)x
AXA-1 = 2xA-1
= 2A-¹x
XI = 2A-¹x
OX44-1
IX = 2XA-1
x = 2A-¹x
x = 2A-¹x
x = 2x4-1
x = 2A-¹x
A ¹x = ¹x
A¹x = 1x
2
A¹x = 1x
A-¹x = ¹x
2
This shows that ---Select--- is an eigenvector of A¹ with eigenvalue ---Select---
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