For affine cipher, the key is a pair (a,b) for a,b<26. The encryption algorithm is E(x)=(ax+b) mod 26. And the decryption algorithm is D(y)=a¹(y-b) mod 26. Note that we map A, B, C, D, ... to numbers 0, 1, 2, 3, ... respectively. Assume that K=(7,3), then E(x)=(7x+3) mod 26, and 7-1-15. Thus D(y)=15(y-3) mod 26. 1. For the key K=(7,3), computer the cipher text for "GOLUNCH" is (please use all capital letters) 2. For the key K=(7,3), try to decrypt the cipher text "YHQQFPGHJF" is (please use all capital letters)
For affine cipher, the key is a pair (a,b) for a,b<26. The encryption algorithm is E(x)=(ax+b) mod 26. And the decryption algorithm is D(y)=a¹(y-b) mod 26. Note that we map A, B, C, D, ... to numbers 0, 1, 2, 3, ... respectively. Assume that K=(7,3), then E(x)=(7x+3) mod 26, and 7-1-15. Thus D(y)=15(y-3) mod 26. 1. For the key K=(7,3), computer the cipher text for "GOLUNCH" is (please use all capital letters) 2. For the key K=(7,3), try to decrypt the cipher text "YHQQFPGHJF" is (please use all capital letters)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![For affine cipher, the key is a pair (a,b) for a,b<26. The
encryption algorithm is E(x)=(ax+b) mod 26. And the
decryption algorithm is D(y)=a¹(y-b) mod 26. Note that we
map A, B, C, D, ... to numbers 0, 1, 2, 3, ... respectively.
Assume that K=(7,3), then E(x)=(7x+3) mod 26, and 7-1-15.
Thus D(y)=15(y-3) mod 26.
1. For the key K=(7,3), computer the cipher text for
"GOLUNCH" is
(please use all capital
letters)
2. For the key K=(7,3), try to decrypt the cipher text
"YHQQFPGHJF" is
(please use all
capital letters)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd311fcf8-f909-4559-a209-ff49a6a07423%2F99660707-9ca9-4b28-bd5e-3005772ec5ed%2Fsq26b6j_processed.png&w=3840&q=75)
Transcribed Image Text:For affine cipher, the key is a pair (a,b) for a,b<26. The
encryption algorithm is E(x)=(ax+b) mod 26. And the
decryption algorithm is D(y)=a¹(y-b) mod 26. Note that we
map A, B, C, D, ... to numbers 0, 1, 2, 3, ... respectively.
Assume that K=(7,3), then E(x)=(7x+3) mod 26, and 7-1-15.
Thus D(y)=15(y-3) mod 26.
1. For the key K=(7,3), computer the cipher text for
"GOLUNCH" is
(please use all capital
letters)
2. For the key K=(7,3), try to decrypt the cipher text
"YHQQFPGHJF" is
(please use all
capital letters)
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