For a short period of time, a m = 3400 kg truck has a frictional driving force of FD= (650- +²) N actingon the wheels, where t is in seconds. At t = 0, the truck has a speed of of v₁.V₁t = 021Values for the figure are given in the following table. Note the figure may not be to scale.VariableValuem5-sv2 =mUsing the Principle of Linear Impulse and Momentum,a. Determine the speed of the truck when t = 3 s, v2.FD = f(t)Round your final answers to 3 significant digits/figures.mSV₂t2

Answered: Image /qna-images/answer/be219f8e-a30a-4066-ba94-2b6d6a5a6478.jpg

Answered: For a short period of time, a m = 3400…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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When a 5000 lb car driven at 60 mph on a level road is suddenly put into neutral gear (i.e. allowed to coast), the velocity decreases in the following manner: 60 V = mph , 1+() where t is the time in sec. Find the horsepower required to drive this car at 30 mph on the same road. Useful constants: 9 = 22 mph/sec, 1 H.P. = 550 ft.lb/sec, 60 mph = 88 ft/sec.
Please answer by own do not copy paste from other answer.
62. •A 5-kg object is constrained to move along a straight line. Its initial speed is 12 m/s in one direction, and its final speed is 8 m/s in the opposite Complete the graph of force versus time with direction. F (N) (s) appropriate values for both variables (Figure 7-26). Several answers are correct, just be sure that your answer is internally consistent. Figure 7-26 Problem 62
Read the peak power and peak torque from the following curve. Also, find the engine speed that the peak power and peak torque occur at, and ensure this engine speed is in Rad/sec. Torque Power N.m kW 40 35 30 25 8020 70 6015 50 40 10 30 20 5 10 00 0 1000 N (C max) N(C min) N (Pmax) 2000 3000 4000 5000 6000 Engine Speed (RPM) g/kWh 400 300 200 100 0 Specific Fuel Consumption
Calculate the ankle torque during initial contact when running from the following data set to 1 decimal place. NOTE if your answer is negative put the negative sign in the answer! Fz 1716 N Fx-560 N COP z 0 m Cop x 0.491 m Ankle z 0.069 m Ankle x 0.566 m e to search Answer: Check P Next page 7°C Light ra
The plot below of load vs. extension was obtained using a specimen (shown in the following figure) of an alloy remarkably similar to the aluminum-killed steel found in automotive fenders, hoods, etc. The crosshead speed, v, was 3.3x104 inch/second. The extension was measured using a 2" extensometer as shown (G). Eight points on the plastic part of the curve have been digitized for you. Use these points to help answer the following questions. 1. 900 800 (0.10, 630 ) 700 (0.50, 745) (0.30, 729) 600 (0.20, 699) (0.40, 741.5) 500- (0.004, 458) (0.80, 440 ) - 400 (0.0018, 405) 300 D= 3.3 " 0.03" 200 G=2.0" 100 - 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 Extension, inches a. Determine the following quamtities. Do not neglect to include proper units in your answer. Young's Modulus Total elongation Yield stress Ultimate tensile strength Uniform elongation Engineering strain rate Post-uniform elongation b. Construct a table with the following headings, left-to-right: Extension, load, engineering strain,…
Can you explain how this can be solved please. Thanks!
solve a and b given in the image provided.
The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093
0.8 m wo B D E 0.8 m 1.0 m Bar AB rotates about the fixed point A with constant angular velocity wo. The system starts with bar AB horizontal. 1) Use the relative velocity equation to find the velocity of C in terms of the angles 0 and > and their derivatives. 2) Determine the lengths of bars AB and BC so that as bar AB rotates, the collar C moves back and forth between the positions D and E. A design constraint is that bar BC must be longer than bar AB (as shown in sketch). 3) You are given the design constraint that the magnitude of the acceleration of collar C must not exceed 200 m/s². What is the maximum allowable value of wo? 4) Create the following plots for a complete revolution of bar AB using the values for lengths and angular velocity determined above: о о e and > versus time as 2 sub-plots. Position, velocity, and acceleration of C versus time as 3 sub-plots. Velocity and acceleration of C versus its position as 2 sub-plots. - 5) Use your plotted results to describe the…
B7
Got this wrong. please help and show work then round the final answer to 3 sig figs.

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