For a normal distribution, use a standard normal distribution table or technology to complete parts a through c. For each part, sketch the normal curve with mean μ and standard deviation o and indicate the area corresponding to the probability. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The probability is 0.159. (Round to three decimal places as needed.) Sketch the normal curve with mean μ and standard deviation and indicate the area corresponding to the probability. Choose the correct graph below. O A. μ-30 O C. μ-20 μ-30 μ-20 P-O μ-a T P μ+a μ+20 + 30 P μ+o Q +20 + 30 b. Find the probability that an observation is at least 1 standard deviation below the mean. ~ The probability is. (Round to three decimal places as needed.) B. B. μ-30 O D. T μ-20 μ-a μ-30 μ-20 P-O T P P p+o μ+o Q ✔ +20 + 30 Q +20 + 30
For a normal distribution, use a standard normal distribution table or technology to complete parts a through c. For each part, sketch the normal curve with mean μ and standard deviation o and indicate the area corresponding to the probability. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The probability is 0.159. (Round to three decimal places as needed.) Sketch the normal curve with mean μ and standard deviation and indicate the area corresponding to the probability. Choose the correct graph below. O A. μ-30 O C. μ-20 μ-30 μ-20 P-O μ-a T P μ+a μ+20 + 30 P μ+o Q +20 + 30 b. Find the probability that an observation is at least 1 standard deviation below the mean. ~ The probability is. (Round to three decimal places as needed.) B. B. μ-30 O D. T μ-20 μ-a μ-30 μ-20 P-O T P P p+o μ+o Q ✔ +20 + 30 Q +20 + 30
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Question 3, 6.2.16

Transcribed Image Text:0
2
-5.0
-4.5
-4.0
-3.5
.00
.000000287
.00000340
.0000317
.000233
Cumulative
probability
Z
.00
.01
.0003
.0005
.02
.0003
.0005
.03
Cumulative probability for z is the area under
the standard normal curve to the left of z
.05
.07
.08
.09
0003
.0003
.0003
.0003
.0002
0004 .0004 .0004
.0004
.0003
0006 0006
.0005
.0005
.0005
0008 .0007
.0007
0011 .0010
.0010
.0008 0008
.0012 .0011 .0011
.0016 .0016 .0015
.0023 .0022
.0021 .0021 0020
0015
0014
.0014
0019
0026
.0031 .0030 .0029 .0028 .0027
.0038 .0037
.0051 .0049
.0041
0036
.0040 .0039
.0054 .0052
.0055
.0048
.0073
.0071
.0069
.0068 .0066 .0064
.0096 .0094
.0091
.0089
.0087
.0084
.0125
0122
.0119
.0116 .0113
.0110
.0162
.0158 .0154 0150 .0146
.0143
.04
-3.4
.0003
.0003
0003
-3.3 .0005
.0004
.0004
-3.2 .0007
.0007 .0006 .0006 .0006
-3.1
.0010
-3.0
.0009 .0009 .0009 .0008
.0013 .0013 .0012
.0017
-2.9
.0018 .0018
.0013
.0019
.0026
-2.7 .0035 .0034 .0033
-28
.0025 .0024
.0023
.0032
-26
.0047
.0045 .0044
.0043
-2.5
.0062
.0060 .0059 .0057
-2.4
0082 .0080
.0078 .0075
0102 .0099
-2.3
0104
0107
-2.2 .0139 0136
.0132
.01 29
-2.1 .0179 0174
0170
.0166
.06

Transcribed Image Text:For a normal distribution, use a standard normal distribution table or technology to complete parts a through c. For each part, sketch the normal curve with mean μ and standard deviation o and
indicate the area corresponding to the probability.
Click here to view page 1 of the standard normal table.
Click here to view page 2 of the standard normal table.
The probability is 0.159.
(Round to three decimal places as needed.)
Sketch the normal curve with mean μ and standard deviation and indicate the area corresponding to the probability. Choose the correct graph below.
O A.
μ-30
μ-20
μ-30 μ-20
T
o-n
o-n
T
μ
r
H+O
μ + 2σ μ + 30
μ+o μ + 2σ μ + 30
b. Find the probability that an observation is at least 1 standard deviation below the mean.
The probability is.
(Round to three decimal places as needed.)
B.
μ-30
μ-30
μ-20 μ-σ
H-20
μ-σ
T
μ
T
μ
μ+o μ + 2σ μ + 30
μ+σ
μ+2σ μ + 30
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