For a lower tail hypothesis test with a sample size of 13 and a .10 level of significance, the critical value of the test statistic t is
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A: Answer: The critical value for a significance level of 0.05 is 1.833.
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A: Answer: Given that, n=250 xn2=4.01 P-value = 0.1347 α=0.05
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A: For Sample 1 x̄1 = 12.2 s1 = 10.5 n1 = 900 For Sample 2 x̄2 = 10.4 s2 = 9.9…
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Q: Two groups of individuals were compared with respect to a high carbohydrate low- fat diet (LF) and a…
A: Given: x¯ 1=47.3x¯2=19.3n1=12n2=13s1=28.3s2= 25.8
Q: Use a 0.01 significance level to test the claim that the mean amount of time spent watching…
A: We want to test the hypothesis
For a lower tail hypothesis test with a
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- The alkaline batteries of a toy car were designed to last 30 hours, on average. However lots of customers complained that the batteries were lasting less than 30 hours. You decided to randomly sample 38 of the batteries. The mean of the sample was 29.3 hours and the standard deviation 2.8 hours. Is there sufficient evidence not support the claim that the mean battery life is less than 30 hours? Perform a hypothesis test at the 5% significance level using the p-value approach. a) State Null and alternative hypothesis b) Find test Statistics c)Find p-value d) ConclusionAccording to a research study, college students spent 24.2 hours doing homework per week last year, on average. A random sample of 16 college students was surveyed and the mean amount of time per week each college student spent on homework was 23.7. This data has a sample standard deviation of 2.2. (Assume that the scores are normally distributed.) Researchers conduct a one-mean hypothesis at the 1% significance level, to test if the mean amount of time college students spend on homework per week is less than the mean amount of time last year. Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ=24.2; Ha:μ>24.2, which is a right-tailed test. H0:μ=24.2; Ha:μ<24.2, which is a left-tailed test. H0:μ=23.7; Ha:μ>23.7, which is a right-tailed test. H0:μ=23.7; Ha:μ<23.7, which is a left-tailed test.In attempting to improve student services, a college investigates its registration process and finds that for 12 randomly selected students, the mean registration time was 73.2 minutes with a standard deviation of 14.2 minutes. Another college finds that for 15 randomly selected students, the mean registration time was 42.3 minutes with a standard deviation of 9.8 minutes. At the 0.01 significance level, test the claim that the two samples came from populations with the same means. Assume equal population variances.
- Two groups were selected for an experiment. The sample data is reported: Group A Group B Sample Mean Spending/day ($) 170 150 Sample Standard deviation ($) 10 5 # of Females 9 7 Sample Size 36 42 a. Set up a 99% confidence interval for the mean difference in spending between the two groups. b. At the 10% level test the alternate hypothesis that group B has lower spending level than Group A.In a study of 809 randomly selected medical malpractice lawsuits, it was found that 509 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Identify the null and alternative hypotheses. The null hypothesis, Ho, is a statement that the value of a population parameter (such as proportion, p, mean, µ, or standard deviation, o) is equal to some claimed value. The alternative hypothesis, H,, is the statement that the parameter has a value that somehow differs from the null hypothesis and uses the inequalities , or #, corresponding to a left, right, or two-tailed test, respectively. 5The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
- In order to compare the durability of four different brands of golf balls (ALPHA, BEST, CENTURY, and DIVOT), the National Golf Association randomly selects balls of each brand and places each ball into a machine that exerts the force produced by a 250-yard drive. The number of simulated drives needed to crack or chip each ball is recorded. Use a significance level of 0.05 to conduct all hypothesis tests and construct confidence intervals. Analysis of Variance Sum of Squares Mean Square F Ratio Prob > F 3 38504.150 9698.400 Source DF BRAND Error C. Total 12834.7 21.1742 <.0001" 16 606.1 19 48202.550 What is the value of the between-treatment variability? 48202.55 9698.4 38504.150 606.1 O 21.1742Q: The dataset (provided below this question) lists the ages of customers at 5 different coffee stores in a major metropolitan city. At the 1% significance level, is there evidence of a difference in the population mean ages between the customers at the five stores. Note: Please only provide the t stat, p-value and the appropraite lower, upper, or two tailed test critical value. Ages of customers in 5 different coffee stores STORE A STORE B STORE C STORE D STORE E 30 33 18 27 34 29 27 32 28 25 21 19 35 27 20 20 40 36 36 45 33 28 15 27 28 29 42 35 29 43 33 34 33 18 35 32 14 23 16 45 8 37 29 18 14 41 23 35 30 28 18 37 40 41 35 21 29 26 38 56 37 41 43 29 33 41 29 23 36 41 39 20 47 29 28 26 25 27 28 32 44 38 40 32 20 14 27 48 42 37 33 38 37 29 31 27 42 41 32 8 35 35 17 26 29 8 23 51 16 13 26 42 36 29 47 20 33 37 38 28 28 16 30 35 47 40 44 42 34 32 22 30 16 26 24 31 35 32 35 23 30 10 22 26 18…Two groups of individuals were compared with respect to a high carbohydrate low-fat diet (LF) and a high-fat low carbohydrate diet (LC). Mood was assessed using a total mood disturbance score where a lower score is associated with a less negative mood. Assuming that the random samples come from independent normal distributions with a common but unknown variance, construct a 95% confidence interval for the difference between the two population means, LC less LF. Group LC LF 28+18.56 28±8.96 28±22.37 28+22.30 n 12 13 mean 47.3 19.3 standard deviation 28.3 25.8
- The critical cutoff(s) for a one-tailed, paired-samples t test with 16 participants at a p level of 0.05 is(are) ___. -2.132 and 2.132 -1.753 or 1.753 -1.746 or 1.746 -2.120 and 2.120Two groups of individuals were compared with respect to a high carbohydrate low- fat diet (LF) and a high-fat low carbohydrate diet (LC). Mood was assessed using a total mood disturbance score where a lower score is associated with a less negative mood. Assuming that the random samples come from independent normal distributions with a common but unknown variance, construct a 95% confidence interval for the difference between the two population means, LC less LF. Group LC LF 28+22.37 28+18.56 28+22.30 28±8.96 n 12 13 mean 47.3 19.3 standard deviation 28.3 25.8Suppose a recent study of Trucks and SUVs gave an average fuel efficiency of 19.2 mpg for Trucks and 21.4 mpg for SUVs. The sample standard deviation for Trucks was 3.2 mpg and 2.8 mpg for SUVs. These results were based on samples of 35 Trucks and 39 SUVs. At the 1% significance level, can we conclude that, on average, SUVs have better fuel efficiency than Trucks? Clearly state the null and alternative hypotheses, use the critical value approach (draw a detailed picture), and write out a detailed conclusion. Organize: Hypotheses: Detailed picture: Detailed conclusion:
