For a Lower one-tailed hypothesis test with a sample size of 23 at a = .05, the critical value for the decision would be: O -1.383 O 1.383 O -1.717 O -1.721 O none of these
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- if Amy Cuddy and her research team originally established a sample size of n=200 (100 in each group) and then discovered that 86% of the high-power group (86 of 100) took a gambling risk while 60% of the low-power group (60 of 100) took the risk, then the p-value would have been much lower than that This p-value would have been less sensitive and would have provided stronger evidence for the researcher's hypothesis. State the p-value, rounding to 5 decimal places.QUESTION 3 A wholesaler must decide how many computers to purchase before they know how many they will be able to sell to local retailers. The wholesaler purchases the computers for S300 each and sells them to retailers for $350 each. If the wholesaler is not able to sell them to a retailer then the wholesaler can return them to the manufacturer (for a refund of the S300 cost), but the wholesaler must pay $40 per computer that it returns to the manufacturer (in shipping, handling, and insurance costs). The following probability distribution describes the number of computers the wholesaler may possibly sell to local retailers: there is a 21% chance that they will sell 900 computers, a 56% chance that they will sell 1200 computers; otherwise, they will sell 1500 computers. What is the expected number of computers the wholesaler will sell? (please round your answer to 1 decimal place)Suppose that a random sample is selected and the following contingency table is obtained. Attribute B1 B2 Attribute 2 60 35 T1 T2 20 50 T3 30 45 T4 50 50 Họ: No association exists between two attributes in the population. H1: An association exists between two attributes in the population. is wanted to test at 5% significance level. What is the decision? A. The null hypothesis can be rejected B. The null hypothesis cannot be rejected
- Given the two independent samples below, conduct a hypothesis test for the desired scenario. Assume all populations are approximately normally distributed. Sample 1 Sample 2 110 n2 : 179 28.9 23.6 81 = 3.8 82 = 3.9 Test the claim: Given the null and alternative hypotheses below, conduct a hypothesis test for a = 0.05. Ho: H1 = 42 Ha: H1 < 42 a. Given the alternative hypothesis, the test is Select an answer b. Determine the test statistic. Round to four decimal places. t = c. Find the p-value. Round to 4 decimals. с. p-value = d. Make a decision. O Fail to reject the null hypothesis. O Reject the null hypothesis.Suppose that in a random selection of 100 colored candies, 22% of them are blue. The candy company claims that the percentage of blue candies is equal to 30%. Use a 0.10 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.3 H₁: p=0.3 O B. Ho: p=0.3 H₁: p=0.3 C. Ho: p=0.3 H₁: p>0.3 O D. Ho: p=0.3 H₁: p<0.3 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 30% B. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 30% O C. Fail to…Suppose that in a random selection of 100 colored candies, 21% of them are blue. The candy company claims that the percentage of blue candies is equal to 20%. Use a 0.10 significance level to test that claim. H, p#0.2 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.)
- Suppose that in a random selection of 100 colored candies, 26% of them are blue. The candy company claims that the percentage of blue candies is equal to 21%. Use a 0.10 significance level to test that claim. a. The test statistic for this hypothesis test is (Round to two decimal places as needed.) b. Identify the P-value for this hypothesis test. (Round to three decimal places as needed.)You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:HoHo : pA=0.1pA=0.1; pB=0.4pB=0.4; pC=0.25pC=0.25; pD=0.25pD=0.25Complete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 4 B 39 C 29 D 25 What is the chi-square test-statistic for this data?χ2=Report all answers accurate to three decimal places.Suppose that in a random selection of 100 colored candies, 25% of them are blue. The candy company claims that the percentage of blue candies is equal to 22%. Use a 0.05 significance level to test that claim. O A. Ho p=0.22 Hy p>0.22 O B. Ho p=0.22 H p 0 22 O C. Ho pt0.22 H p=022 O D. Ho p=0.22 H1 p<0.22 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed ) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is | (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 22% O B. Reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 22% OC. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the…
- A fast-food restaurant claims that a small order of french fries contains 120 calories. A nutritionist is concerned that the true average calorie count is higher than that. The nutritionist randomly selects 35 small orders of french fries and determines their calories. The resulting sample mean is 155.6 calories, and the pp-value for the hypothesis test is 0.00093. Which of the following is a correct interpretation of the p-value? A)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more. B) If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or less. C)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more, or a sample mean of 84.4 calories or less. .D)If the population mean is 155.6 calories, the p -value of 0.00093…With the information provided, determine which hypothesis test is required, and per- form it as asked. A frequency table for two categorical variables X and Y, each with two levels, a = 0.05 significance level? given below. Is there evidence of a relationship between them at the X1 X2 Y1 101 81 Y2 35 52 (a) What are Ho and HA? (b) What is the relevant test statistic and its sampling distribution under the null hypothesis? (c) Calculate the test statistic and provide the value. Show working. (d) Using your preferred method (RoR, p-value, CI) make a determination about the hypothesis test.You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:HoHo : pA=0.5pA=0.5; pB=0.3pB=0.3; pC=0.1pC=0.1; pD=0.1pD=0.1Complete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 55 B 32 C 14 D 24 What is the chi-square test-statistic for this data?χ2=χ2= Report all answers accurate to three decimal places.