For a gas mixture that contains 30% propane and 70% n-butane, write out the temperature- dependent equation for the heat capacity of the mixture Comix: Then calculate the value of the enthalpy change for one mole of this gas mixture being heated from 30 °C to 155 °C. Species MW State Range Form Temp a b C d * 10- -12 Unit * 10-3 * 10-5 * 10-8 Units of T Propane 44.09 G 1 °C Butane 58.12 g 1 °C 92.30 68.032 22.59 27.88 -13.11 31.71 -15.47 34.98 0-120 0-1200 Mixtures (Cp) mix (T) = Σ VG (1) all mix comp kJ (Cp) mix mol * °C] = = 0.300+ (0.068032 + 22.59 * 10¯5T - 13.11 * 10−8T² + 31.71 * 10-1273) +0.700(0.09230 +* 27.88 * 10¯5T − 15.47 × 10¯8T² + 34.98 * 10-12³) ΔΗ = - = 0.441872 + 0.0111527 - 19.298 * 10-872 + 45.702 * 10-12T3 .155 30 T2 T3 T41 * (0.441872 + 0.011152T – 19.298 * 10¯©T² + 45.702 × 10−¹²™³)dT eval at upper bound 155, lower bound30 and add 2'3'4 ΔΗ = 269.07- kJ for heating 1 mole of the gas mixture. mol
For a gas mixture that contains 30% propane and 70% n-butane, write out the temperature- dependent equation for the heat capacity of the mixture Comix: Then calculate the value of the enthalpy change for one mole of this gas mixture being heated from 30 °C to 155 °C. Species MW State Range Form Temp a b C d * 10- -12 Unit * 10-3 * 10-5 * 10-8 Units of T Propane 44.09 G 1 °C Butane 58.12 g 1 °C 92.30 68.032 22.59 27.88 -13.11 31.71 -15.47 34.98 0-120 0-1200 Mixtures (Cp) mix (T) = Σ VG (1) all mix comp kJ (Cp) mix mol * °C] = = 0.300+ (0.068032 + 22.59 * 10¯5T - 13.11 * 10−8T² + 31.71 * 10-1273) +0.700(0.09230 +* 27.88 * 10¯5T − 15.47 × 10¯8T² + 34.98 * 10-12³) ΔΗ = - = 0.441872 + 0.0111527 - 19.298 * 10-872 + 45.702 * 10-12T3 .155 30 T2 T3 T41 * (0.441872 + 0.011152T – 19.298 * 10¯©T² + 45.702 × 10−¹²™³)dT eval at upper bound 155, lower bound30 and add 2'3'4 ΔΗ = 269.07- kJ for heating 1 mole of the gas mixture. mol
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
For a gas mixture that contains 30% propane and 70% n-butane, write out the temperature-dependent equation for the heat capacity of the mixture Cp,mix. Then calculate the value of the enthalpy change for one mole of this gas mixture being heated from 30 °C to 155 °C.
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![For a gas mixture that contains 30% propane and 70% n-butane, write out the temperature-
dependent equation for the heat capacity of the mixture Comix: Then calculate the value of
the enthalpy change for one mole of this gas mixture being heated from 30 °C to 155 °C.
Species
MW
State
Range
Form Temp
a
b
C
d * 10-
-12
Unit
* 10-3
* 10-5
* 10-8
Units of
T
Propane 44.09
G
1
°C
Butane 58.12 g
1
°C
92.30
68.032 22.59
27.88
-13.11 31.71
-15.47 34.98
0-120
0-1200
Mixtures
(Cp) mix (T)
=
Σ VG (1)
all mix comp
kJ
(Cp) mix mol * °C]
=
= 0.300+ (0.068032 + 22.59 * 10¯5T - 13.11 * 10−8T² + 31.71 * 10-1273)
+0.700(0.09230 +* 27.88 * 10¯5T − 15.47 × 10¯8T² + 34.98 * 10-12³)
ΔΗ
=
-
= 0.441872 + 0.0111527 - 19.298 * 10-872 + 45.702 * 10-12T3
.155
30
T2 T3 T41
*
(0.441872 + 0.011152T – 19.298 * 10¯©T² + 45.702 × 10−¹²™³)dT
eval at upper bound 155, lower bound30 and add
2'3'4
ΔΗ = 269.07-
kJ
for heating 1 mole of the gas mixture.
mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd47fc2c3-8f4b-4085-b234-bc909be774e3%2F3e51e60f-609a-4a45-acf7-4e39dc3bfcb5%2Fnf42ph_processed.png&w=3840&q=75)
Transcribed Image Text:For a gas mixture that contains 30% propane and 70% n-butane, write out the temperature-
dependent equation for the heat capacity of the mixture Comix: Then calculate the value of
the enthalpy change for one mole of this gas mixture being heated from 30 °C to 155 °C.
Species
MW
State
Range
Form Temp
a
b
C
d * 10-
-12
Unit
* 10-3
* 10-5
* 10-8
Units of
T
Propane 44.09
G
1
°C
Butane 58.12 g
1
°C
92.30
68.032 22.59
27.88
-13.11 31.71
-15.47 34.98
0-120
0-1200
Mixtures
(Cp) mix (T)
=
Σ VG (1)
all mix comp
kJ
(Cp) mix mol * °C]
=
= 0.300+ (0.068032 + 22.59 * 10¯5T - 13.11 * 10−8T² + 31.71 * 10-1273)
+0.700(0.09230 +* 27.88 * 10¯5T − 15.47 × 10¯8T² + 34.98 * 10-12³)
ΔΗ
=
-
= 0.441872 + 0.0111527 - 19.298 * 10-872 + 45.702 * 10-12T3
.155
30
T2 T3 T41
*
(0.441872 + 0.011152T – 19.298 * 10¯©T² + 45.702 × 10−¹²™³)dT
eval at upper bound 155, lower bound30 and add
2'3'4
ΔΗ = 269.07-
kJ
for heating 1 mole of the gas mixture.
mol
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