For a certain knee surgery, a mean recovery time of 9 weeks is typical. With a new style of physical therapy, a researcher dlaims that the mean recovery time,ETu, is less than 9 weeks. In a random sample of 84 knee surgery patients who practiced this new physical therapy, the mean recovery time is 8.9 weeks. Assumethat the population standard deviation of recovery times is known to be 0.9 weeks.Is there enough evidence to support the claim that the mean recovery time of patients who practice the new style of physical therapy is less than 9 weeks?Perform a hypothesis test, using the 0.05 level of significance.(a) State the null hypothesis H, and the alternative hypothesis H.Hg: 0OsOO20O=0?(b) Perform a Z-test and find the p-value.Here is some information to help you with your Z-test.• The value of the test statistic is given by• The p-value is the area under the curve to the left of the value of the test statistic.Standard Normal Distribution0.4Step 1: Select one-tailed or two-tailed.O One-tailedO Two-tailedStep 2: Enter the test statistic.(Round to 3 decimal places.)02-Step 3: Shade the area represented bythe p-value.Step 4: Enter the p-value.(Round to 3 decimal places.) (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the researcher.O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there isenough evidence to support the claim that the mean recovery time of patients who practice the new style of physicaltherapy is less than 9 weeks.O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there isnot enough evidence to support the claim that the mean recovery time of patients who practice the new style ofphysical therapy is less than 9 weeks.O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enoughevidence to support the claim that the mean recovery time of patients who practice the new style of physical therapyis less than 9 weeks.O ince the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enoughevidence to support the claim that the mean recovery time of patients who practice the new style of physical therapyis less than 9 weeks.

For the given data Perform Z test for one mean

Answered: For a certain knee surgery, a mean…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

A company that runs a chain of quick oil change centers, tries to attract customers by claiming that it completes oil changes faster than its competition. So it periodically estimates the time taken to do oil changes at its centers. From historical records, the company knows that the population standard deviation of oil change duration is 15 minutes. Recently, 40 customers were asked how much time they spent getting an oil change at one of their centers. Based on the sample data, the chain concluded that the average oil change time for the population of all its customers was between 15 and 25 minutes. What was the confidence level at which the inference was made?
For a certain knee surgery, a mean recovery time of 13 weeks is typical. With a new style of physical therapy, a researcher claims that the mean recovery time, μ, is less than 13 weeks. In a random sample of 32 knee surgery patients who practiced this new physical therapy, the mean recovery time is 12.8 weeks. Assume that the population standard deviation of recovery times is known to be 1.1 weeks. Is there enough evidence to support the claim that the mean recovery time of patients who practice the new style of physical therapy is less than 13 weeks? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. H Ho: O H₁:0 OO 020 ローロ OO ? (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by x-μ √n • The p-value is the area under the curve to the left of the value of the test statistic. Standard Normal Distribution 04 Step 1:…
A medical journal published the results of a study to compare the effectiveness of handwashing with soap and handrubbing with alcohol. Health care workers who used handrubbing had a mean bacterial count of 34 per hand with a standard deviation of 65. Health care workers who used handwashing had a mean bacterial count of 67 per hand with a standard deviation of 103. In a random sample of 50 health care workers, all using the same method of cleaning their hands, the mean bacterial count per hand, x, is less than 33. Give your opinion on whether this sample of workers used handrubbing with alcohol or handwashing with soap. Click the icon to view the table of normal curve areas. Since the probability of x being less than 33 is alcohol, and used if this sample of workers used handrubbing with ▼if they used handwashing with soap, it is more likely that this sample of workers
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like?
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like? Reject H0 if z is less than or equal to –2.326. Reject H0 if z is greater than or equal to 2.326. Reject H0 if z is less than or equal to –2.576. Reject H0 if z is greater than or equal to 2.5760
A particular IQ test is standardized to a Normal model, with a mean of 80 and a standard deviation of 8. A group of 8,000 people had participated in a study based on IQ. Using the Empirical rule determine about how many of them should have IQ scores more than 72?
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99
A marine biologist claims that a harbor seal's average dive time is at least 5.8 minutes. A random sample of 35 dive durations has a mean of 4.9 minutes and a standard deviation of 1.8 minutes. Is there enough evidence to reject the claim at a = 0.01?
Using traditional methods, it takes 98 hours to receive a basic driving license. A new license training method using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique with 270 students and observed that they had a mean of 97 hours. Assume the standard deviation is known to be 7. A level of significance of 0.1 will be used to determine if the technique performs differently than the traditional method. Is there sufficient evidence to support the claim that the technique performs differently than the traditional method? What is the conclusion?
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like? Reject H0 if z is less than or equal to –2.326. Reject H0 if z is greater than or equal to 2.326. Reject H0 if z is less than or equal to –2.576. Reject H0 if z is greater than or equal to 2.5760

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS