14. Please show the solution in detail For a body to be in static equilibrium under the combined action of several forcesO all of the forces form pairs of equal and opposite forcesO all the force must be applied at the same pointO any two of these forces must be balanced by a third forceO the sum of the torque about any point must equal zeroO the lines of action of all the forces must pass through the center of gravity of the body

For a body to be in static equilibrium under the combined action of several forces, the net force on the body and the net torque on the body must be equal to zero. Suppose a child’s seesaw with two children sitting at the ends of the seesaw. The weights of the children are different and hence the force are also not equal to each other. The seesaw also has some mass.If the seesaw with the children is in static equilibrium, then the net torque about any point is equal to zero. The lines of action not necessarily to be passed through the center of gravity. As well as all the forces need not be applied at the same point. If there are only three forces present on the body then any of the two forces must be balanced by the third one. Thus, the 3rd and 4th options are correct.

Science

Advanced Physics

For a body to be in static equilibrium under the combined action of several forces all of the forces form pairs of equal and opposite forces all the force must be applied at the same point any two of these forces must be balanced by a third force O the sum of the torque about any point must equal zero O the lines of action of all the forces must pass through the center of gravity of the body

For a body to be in static equilibrium under the combined action of several forces all of the forces form pairs of equal and opposite forces all the force must be applied at the same point any two of these forces must be balanced by a third force O the sum of the torque about any point must equal zero O the lines of action of all the forces must pass through the center of gravity of the body