For a 3 sigma control chart of the process mean, the expected ARL when the process is currently in control is approximately 500. alect one:
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- A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new test are 60% and 70%, respectively. Five hundred people are screened at a clinic during the first year the new test is implemented. Assume the true prevalence of Lyme disease among clinic attendees is 10%. Calculate the predictive value of a positive test.In a population-based cohort study, an entire community was interviewed regarding smoking habits and then followed for one year. Upon ascertainment of all lung cancer deaths, the investigator obtained the following data: Number of Individuals Lung Cancer Deaths Smokers 24,500 15 Nonsmokers 10,500 2 Calculate the risk difference per 100,000 per year. Round to the tenth decimaA 2019 study surveyed Norwegian parents about their children's eating habits and taste sensitivities. We are interested in seeing if there is a relationship between sensitivity to sweetness and emotional overeating. The study reports an F* = 2.34 with dfb 3 and dfw = 96. How many levels of 'sensitivity to sweetness' were used in the study? How many subjects participated in the entire study?
- Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most 150°F, there will be no negative effects on the river's ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above 150°, 50 water samples will be taken at randomly selected times and the temperature of each sample recorded. The resulting data will be used to test the hypotheses Ho: μ = 150° versus H₂: μ > 150°. In the context of this situation, describe type I error. a A type I error occurs when our estimate for the mean discharge temperature is higher than the actual temperature. A type I error occurs when we say that the plant is not in compliance when in fact it is. A type I error occurs when our estimate for the mean discharge temperature is lower than the actual temperature. A type I error occurs when we…Please see attachedConsider a simple logistic model in which the response variable is attendance at a conference (yes = 1; no = 0), and the sole independent variable is a college degree (degree = 1; no degree = 0). The estimated odds ratio for the college degree variable is 1.25. What is its proper interpretation?
- Citrus Rental is a popular car rental agency that has a history of having too few cars available, so that its available cars are overdriven. The mean monthly mileage over the years for Citrus cars has been about 1550 miles per month. Recently, though, Citrus purchased thousands of new cars, and the company claims that the average mileage of its cars is now less than in the past. To test this, a random sample of 13 recent mileages of Citrus cars was taken. The mean of these 13 mileages was 1425 miles per month, and the standard deviation was 209 miles per month. Assume that the population of recent monthly mileages of Citrus cars is normally distributed. At the 0.10 level of significance, can it be concluded that the mean recent monthly mileage, μ, of Citrus cars is less than 1550 miles per month? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary,…Time to Complete the Course Right 45 47 50 49 50 50 48 44 Left | 45 | 43 48 47 50 52 | 44 42 Assume a Normal distribution. What can be concluded at the the a = 0.01 level of significance level of significance? For this study, we should use t-test for the difference between two dependent population means a. The null and alternative hypotheses would be: p1 p2 Ні: p1 p2 b. The test statistic t v v = 1.199 (please show your answer to 3 decimal places.) c. The p-value = [1338 your answer to 4 decimal places.) d. The p-value is > va e. Based on this, we should fail to reject f. Thus, the final conclusion is that ... * (Please show v the null hypothesis. O The results are statistically insignificant at a = 0.01, so there is insufficient evidence to conclude that the population mean time to complete the obstacle course with a patch overSuppose that having a widow's peak was a dominant trait (W) compared to not having a widow's peak (w). In a sample size of 30 students, 15 were observed to have a widow's peak and 15 did not have a widow's peak. The expected frequency of a widow's peak is 75% chance of getting it and a 25% chance of not getting it. Perform a chi square analysis to see if the data above agrees with the predicted outcome.
- In a random sample of sixteen different industries the percentage employment x in STEM (science, technology, engineering, mathematics) and mean annual compensation y(in thousands of dollars) were recorded, with the following results. The scatter diagram showed a linear trend. SSx = 1303.9 SSsy= 1503.0 SSy = 2660.2 Ey = 915 n= 16 %3D Ex = 150 .1 1sx<34 36.7 s y < 90.5 Predict the mean annual compensation in industries in which 30 percent of the workforce are in a Stem field. You answer should be entered in thousands of dollars. Example: If you calculate y-hat as 40.6 then the answer you enter should be 40,600You believe that your morning commute to UCLA is decreasing every week. You record thetime of 7 commutes (one for each day of the week) (in minutes) for the a one-week block and thenthe following one-week block. * Calculations have been done for you: the sample mean difference is -1.714 and the sample standarddeviation is 2.984. Conduct a hypothesis test at the α = 0.15 level. The mean difference calculated as the the first one-week block minus the second one-week block. That is to say week one minus week two. a. Set up the null and alternative hypothesis (using mathematical notation/numbers and interpretthem in context of the problem) b. Calculate the test statistic for the test from part a4. 0 There is some indication that as countries' levels of literacy increases, authoritarian tendencies decline among the population. The following data show literacy (measured in number of literate people per 10 people) and authoritarian scores on a standard authoritarinaism- measuring scale from 8 countries. The data are: Xiiteracy : 9.2, 7.5, 8.8, 6.5, 4.3, 5.9, 9.7, 8.5 XAuth: 2.1, 3.4, 2.5, 7.3, 8.9, 5.7, 1.3, 2.5 Is there a reliable relationship between the two variables? If yes, what would the predicted authoritarian score of a country where only quarter of the country is literate? What about for a country where the literacy rate is %100? Use alpha = .05.
