For -11 < a < 12 the function f is defined by f(x) = x²(x + 7)² On which two intervals is the function increasing (enter intervals in ascending order)? X = and X = to x = to x = Find the interval on which the function is positive: x = Where does the function achieve its absolute minimum? x = to x=

Q: 4 3- 1 -6 -5 -4 -3 -2 2 3 4 6. 2 -3 4 2. 3.

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Q: 3

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Q: 5.1 #7

A: Given that                  A=60-1054-403-3502-425, λ=5

Q: -7.4v+2.4(-7.1v+-10)+6.7

A: simplified value is -24.44 v - 17.3

Q: 10.0

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Q: d) | 4f(x)| dæ =

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A: To simplify the expression means writing it in the simplest form.

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A: We can solve this using given information

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Q: -96 6 -7 A = -3 d 4A.

A: