Foom 33* x ( cox?o + kim°8) = (-36.48-Lcosi46'51')- + (-14.52 - 2 kimlu6 si')- %3D う = 14.97 m 三
Foom 33* x ( cox?o + kim°8) = (-36.48-Lcosi46'51')- + (-14.52 - 2 kimlu6 si')- %3D う = 14.97 m 三
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
How to solve the value 14.97? The solution was not kind of clear, please explain.

Transcribed Image Text:3. Given the following data of a closed traverse
LINE
DISTANCE (m)
BEARING
1-2
31.20
N 15°24' E
2-3
28.50
S 82°32' E
3-4
S 33°09' E
4-5
33.00
5-1
24.23
N 65°21' W
a. Determine the distance of line 3-4
b. Determine the bearing of line 4-5

Transcribed Image Text:Foom
3* x ( en*o + cin°e) - (-36-48 -LesI46'si')
+ (-14,52 - 1 kimiy46 si')?
う
14.97 m
%3D
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