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Following the ideas above, show that this data illustrates the law of multiple proportions. (Compare the masses of bromine that react with 1.00 g of gold). Two compounds of gold and bromine have these percent compositions: Compound X is 45.11% Au and 54.89% Br, Compound Y is 71.14% Au and 28.86% Br

Following the ideas above, show that this data illustrates the law of multiple proportions. (Compare the masses of bromine that react with 1.00 g of gold). Two compounds of gold and bromine have these percent compositions: Compound X is 45.11% Au and 54.89% Br, Compound Y is 71.14% Au and 28.86% Br

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Following the ideas above, show that this data illustrates the law of multiple proportions. (Compare the masses of bromine that react with 1.00 g of gold).

Two compounds of gold and bromine have these percent compositions:

Compound X is 45.11% Au and 54.89% Br,

Compound Y is 71.14% Au and 28.86% Br

Consider the formulas of carbon monoxide (CO) and carbon dioxide (CO2). A quick examination of the molecular formulas shows that the ratio of carbon to oxygen in CO is 1:1, whereas in CO2 it is 1:2. It can also be stated that the ratio of oxygen in CO, to oxygen in CO is 2:1. Before chemists had knowledge of chemical formulas, this simple ratio of C:0 in carbon monoxide and carbon dioxide had been observed. Observations such as this were key in developing the law of multiple proportions and formulas for compounds. To see how this law came about, consider the following data for two compounds of iron and chlorine: Compound A was 34.42% Fe and 65.58% CI Compound B was 44.05% Fe and 55.95% CI Consider 100 g of compound A 34.42 g of iron reacts with 65.58 g of chlorine 1.00 g of iron reacts with x g of chlorine Consider 100 g of compound BỊ 44.05 g of iron reacts with 55.95 g of chlorine 1.00 g of iron reacts with y g of chlorine Using the idea of definite proportions: 65.85 34.42 55.95 = 44.05 1.00 1.00 X = 1.905 у 3 1.270 1.00 g of iron reacts with 1.91 g of chlorine 1.00 g of iron reacts with 1.27 g of chlorine Finally, compare (by division) the two amounts of chlorine that reacted with 1.00 g of iron: 1.905 = 1.500 = 3:2, which is a simple ratio 1.270 1 From our viewpoint looking back we can see that the compounds A and B are FeCl, and FeCl2
Transcribed Image Text:Consider the formulas of carbon monoxide (CO) and carbon dioxide (CO2). A quick examination of the molecular formulas shows that the ratio of carbon to oxygen in CO is 1:1, whereas in CO2 it is 1:2. It can also be stated that the ratio of oxygen in CO, to oxygen in CO is 2:1. Before chemists had knowledge of chemical formulas, this simple ratio of C:0 in carbon monoxide and carbon dioxide had been observed. Observations such as this were key in developing the law of multiple proportions and formulas for compounds. To see how this law came about, consider the following data for two compounds of iron and chlorine: Compound A was 34.42% Fe and 65.58% CI Compound B was 44.05% Fe and 55.95% CI Consider 100 g of compound A 34.42 g of iron reacts with 65.58 g of chlorine 1.00 g of iron reacts with x g of chlorine Consider 100 g of compound BỊ 44.05 g of iron reacts with 55.95 g of chlorine 1.00 g of iron reacts with y g of chlorine Using the idea of definite proportions: 65.85 34.42 55.95 = 44.05 1.00 1.00 X = 1.905 у 3 1.270 1.00 g of iron reacts with 1.91 g of chlorine 1.00 g of iron reacts with 1.27 g of chlorine Finally, compare (by division) the two amounts of chlorine that reacted with 1.00 g of iron: 1.905 = 1.500 = 3:2, which is a simple ratio 1.270 1 From our viewpoint looking back we can see that the compounds A and B are FeCl, and FeCl2
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