Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 0.5 D, = 17 + 24 \Pa

Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 0.5 D, = 17 + 24 \Pa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laboratory Determination of Hydraulic Conductivity

Hydraulic conductivity is the measure of flowability of water inside the soil in the presence of a hydraulic gradient. The hydraulic gradient is defined as the difference in the water heads in the soil, which induces a water motion. In simple terms, a hydraulic gradient is the presence of a potential that induces a flow of water.

Question

Refer to Problem 3.4. Using Eq. (3.22), determine the average relative density of sand.

Following is the variation of the field standard penetration number (N0) in a sand
deposit:
Depth (m)
1.5
3
8
4.5
9.
6
8
7.9
13
14
The groundwater table is located at a depth of 6 m. Given: the dry unit weight of
sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for
depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the
corrected penetration numbers.

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Answer 4.8
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