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Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 0.5 D, = 17 + 24 \Pa

Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers. 0.5 D, = 17 + 24 \Pa

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Refer to Problem 3.4. Using Eq. (3.22), determine the average relative density of sand.

Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers.
Transcribed Image Text:Following is the variation of the field standard penetration number (N0) in a sand deposit: Depth (m) 1.5 3 8 4.5 9. 6 8 7.9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m², and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m³. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers.
0.5 D, = 17 + 24 \Pa
Transcribed Image Text:0.5 D, = 17 + 24 \Pa
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