Following is the result of a modified proctor test. Determine the maximum dry unit weight, void ratio and saturation at optimum moisture content and energy of compaction. Make a tabulation of all your results. Volume of Mold (m³)Weight of Moise Soil in Mold (kN)Moisture Content0.0009450.0162100.0009450.0172OF120.0009450.0179140.0009450.0177160.0009450.0173180.0009450.016620

Answered: Image /qna-images/answer/1f1923e2-740b-467e-9a89-b05f4c1dcd7d.jpg

Answered: Following

Engineering

Civil Engineering

Following

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: atory apparatus for the following Label and give the use/uses. 1. Determination of moisture content…

A: Note- We are authorized to answer three subparts at a time since you have not mentioned which part…

Q: A compaction test was conducted and standard Proctor compaction procedure was used. The weight of a…

A: To Find :- wet and dry unit weight of compacted soil specimen in lb/ft^3 Given:- Mold + Compacted…

Q: d) A sample of silty clay has a mass of 126 g. Laboratory tests results give a bulk density (p») of…

A: Given data, Mass m = 126 g Bulk density ρb = 2.05 g/cm3 = 2050 kg/m3 Bulk unit weight γb = 20.10…

Q: Following the sieve analysis and the specific gravity of "SAND 1", a hydrometer test was performed…

A: The hydrometer test is used to determine the distribution of soil particle sizes that are smaller…

Q: 2) A moist sample was found to have a volume of 22.3 cubic centimeters and to weigh 29.7 grams. The…

Q: Following are the results from the liquid and plastic limit test for a soil Plastic limit = 12.2%…

A: Plastic limit=12.2% Moisture content=26.5%

Q: A field technician submits the results of a sand cone test for review. Prior to the test, the…

Q: The total volume of a soil specimen is 80,000 mm3 and it weighs 150 grams. The dry weight of the…

A: Find the following: a) The water content. b) Void Ratio. e) Porosity. d) Degree of saturation. e)…

Q: Table Q2: Result of Standard Proctor Test Mass of wet soil in the mold (kg) Moisture content (%)…

A: Weight Moisture content Unit weight Dry Unit weight 1.68 9.9 1780.98166 1620.547461 1.71 10.6…

Q: The maximum and minimum dry unit weights of a sand were determined in the laboratory to be 16.9 kN/m…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

Q: Derive the relation between void ratio (e), specific gravity of particles (G) and moisture content…

Q: Show calculation on how to determine the maximum dry density and the optimum moisture content.…

A: weight of wet soil (kg) water content dry weight of soil (gm) volume of mould(cm3) dry…

Q: The following are the data of the compaction test: Volume of mold = 0.000945 m^3 Determine the…

A: Calculation of water content water content=wwws

Q: A standard compaction test was performed in the laboratory and the follows: Trial Number 2 3 4 Moist…

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

Q: A compacted fill with a unit weight of 121 lb/ft^3 and a moisture content of 12.5% will be used for…

A: The dry unit weight of the soil in compacted fill is calculated as, γd=γb1+w=1211+0.125=107.56…

Q: A given soil sample is taken from the field by Bubba Lesh for compaction testing. Before compaction,…

A: solutioncompaction is defined as removal of air from the soil present in the voids compaction is…

Q: A sample of field soi! is tested in the laboratory. The results of Standard Proctor test at optimum…

A: Degree of compaction Soil compaction is the process of applying mechanical compaction effort to the…

Q: Results of a standard Proctor compaction test on a silty sand are shown in the below figure. Dry…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three subparts…

Q: 2) A moist sample was found to have a volume of 22.3 cubic centimet grams. The dry weight of the…

A: Given : Volume of moist sample = 22.3 cm3 weight = 29.7 grams dry weight of sample = 23 grams…

Q: A standard compaction test was carried out in a mould of volume 0.001 m³1. Test results ar tabulated…

A: V = 0.001 m3Gs = 2.67

Q: Determine the degree of saturation in percentage in a bulk density determination procedure on a…

Q: A standard compaction test was performed in the laboratory and the results are tabulate follows:…

Q: The results of a Standard Proctoretest is tabulated as follows: (CHECK PICTURE) Determine the…

Q: A sample of soil was retrieved and tested in the laboratory. Its water content was 29%, the bulk…

A: Given information: So, the void ratio =e = 0.816

Q: A 443 gram, 42.8 mm diameter by 97 mm long clay specimen was tested in a triaxial test. After…

Q: A loose uncompacted sand fill 5 ft in depth has a relative density of 40%. Laboratory tests…

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

Q: A compaction test was conducted in a soils laboratory using the Standard Proctor Method B test…

A: In a standard proctor test of a sample The weight of the compact soil specimen plus mold and the…

Q: A representative soil specimen collected from the a construction site weighs 1,8kN and has a volume…

Q: A Standard Proctor compaction test performed on a sample of crushed limestone (G; = 9.70) obtained a…

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

A: Solution:-The given data ,Water content (w)=8%=0.08The degree of saturation(S)=42%=0.42Specific…

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

Q: What is the natural moisture content of soil in percent? b. Compute the consistency index.

A: AS CONSISTANCY INDEX + LIQUIDITY INDEX =1

Q: A sand sample has a porosity of 30% and specific gravity of solids as 2.6. What is its degree of…

A: given- porosity n=30%G=2.6moisture content w=4.94%

Q: A sand sample has a porosity of 30% and specific gravity of solids as 2.6. What is its degree of…

A: Given data Porosity (n) = 30% = 0.3 Specific gravity of solid (Gs) = 2.6 Mositure content (w) =…

Q: PROBLEM: GIVEN: Lab data for Modified Compaction Test REQUIRED: 1. Compute Wet & Dry Density of each…

A: wt of wet soil (w1) in gm wt of dry soil w2 in gm wt of water=w1-w2 in gm moisture content=w1-w2w2…

Q: plume of Proctor Mold (cm³) Moisture Content (w% mold (kg) 943.3 1.65 5.5 943.3 1.70 7.3 943.3 1.80…

A: Yd = dry unit weight w = moisture content Yb = wet unit weight / bulk density

Q: a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After…

A: Given : Water content = 8% Degree of saturation = 42 % Altered degree of saturation = 53 % the…

Concept explainers

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.

Question

Following is the result of a modified proctor test. Determine the maximum dry unit weight, void ratio and saturation at optimum moisture content and
energy of compaction. Make a tabulation of all your results.

Volume of Mold (m³)
Weight of Moise Soil in Mold (kN)
Moisture Content
0.000945
0.0162
10
0.000945
0.0172
OF
12
0.000945
0.0179
14
0.000945
0.0177
16
0.000945
0.0173
18
0.000945
0.0166
20

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A sample of saturated soft clay has a moisture content of w. The specific weight of solids é ys em g-f/cm' (Table 1). What is the void index, porosity and saturated specific weight of the soil (in g-f/cm). Adopt water specific weight of 1 g-f/cm3.
a soil sample was determined to have a water content of 8% and a degree of saturation of 42%. After adding some water, the degree of saturation was altered to 53%. take the specific gravity of the soil solids to be 2.7. assuming no change in the volume of the voids, determine the following A. void ratio B. water content% C. bulk specific gravity of the mass of the sample in the altered state.
6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1,83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2
The wet weight of a soil specimen is 207 g. The dried weight of the specimen is 163 g. If the volume of the specimen is measured before drying is 110 cubic centimeter, determine the Void ratio if specific gravity of solids is 2.68.
Problem Set 2: 4. A sample of gray silty clay has a mass of 126 kg. Laboratory tests results give a moist density (p) of 2.05 g/cm³, a specific gravity of solids (G,) of 2.71, and a moisture content (w) of 15.7%. First determine all entries in the phase diagram. Then determine the void ratio (e), the porosity (n), the degree of saturation (S), the dry density (Pa), the dry unit weight (ya), and the moist unit weight (y). Draw the Phase diagram.
please answer all parts
A compaction test was conducted in a soils laboratory using the Standard Proctor Method B test procedure. The weight of the compact soil specimen plus mold and baseplate was determined to be 3841 g. The volume and mass of the mold were 943.7 cm³ and 2066.0 g, respectively. A moisture content test was carried out on a representative portion of the sample and the results were 9.8%. Required Determine the dry unit weight in metric units, to the nearest 100th. Your Answer:
Please answer the following questions. In solving the problems, you should use stored values to get the exact values.
Results of a standard Proctor compaction test on a silty sand are shown in the below figure. Dry unit weight (kN/m³) 19.5 19.0 18.5 18.0 6 17.5 17.0 5-17 7-12 8-11 a. What is the moist unit weight (ywet, kN/m3) at optimum moisture content? b. What is the degree of saturation (Sr, %) at optimum moisture content? Given: Gs = 2.73. c. If the required field dry unit weight (yd) is 18.15 kN/m3, what is the relative compaction (%)? 6. What should be the range of compaction moisture contents (%) in the field to achieve the above relative compaction? 10 0 6-14 5 9.5-10.5 10 Moisture content (%) 15 20 7. If the minimum and maximum void ratios are 0.29 and 0.80, respectively, what is the relative density of compaction in the field (%)?
A modified Proctor compaction test was carried out using a cylindrical moldwith a 1000 ml volume. Table 2 summarizes the results. a. Plot the compaction and ZAV curves (RD=2.75 and ρwater=1000 kg/m3)b. Determine the maximum dry density and the optimum moisture content Table 2 Moisture Content (%)Mass of WetSample (g)10.5 2033.211.8 2146.613.0 2203.514.9 2183.116.4 2147.617.6 2116.8