Results of a standard Proctor compaction test on a silty sand are shown in the below figure. Dry unit weight (kN/m³) 19.5 19.0 18.5 18.0 17.5 17.0 0 5 10 Moisture content (%) 15 void curve 20 a. What is the moist unit weight (ywet, kN/m3) at optimum moisture content? b. What is the degree of saturation (Sr, %) at optimum moisture content? Given: Gs = 2.73. c. If the required field dry unit weight (yd) is 18.15 kN/m3, what is the relative compaction (%)?

Q: The value of coefficient of permeability for a uniformly graded sand of size D10 = 0.20 cm obtained…

A:

Q: A clayey sand (SC) was compacted into a 1/30th cubic foot cylindrical Proctor steel mold with the…

A: Given:Volume of the mold (V) = 1/30 ft3 Weight of dry soil (Wd) = 4.18 lbWeight of wet soil (W) =…

Q: The following values for sand are given: D = 0.28 mm ,D=0.45 mm ,D 10 30 0.7mm. 60%D Determine C…

A: Determine (Coefficient of uniformity) and  (Coefficient of curvature) and state if it is a well…

Q: a sample of silty sand in a 150 mm diameter mold. The maximum dry unit weight is 19.6 kN/m3 and…

A: According to given data  A modified proctor compaction test is performed on a sample of silty sand…

Q: ctivity 3 Problem Set Questions Liquid Limit and Plastic Limit Tests were conducted on a soil given…

A:

Q: The value of coefficient of permeability for a uniformly graded sand of size D10 = 0.20 cm obtained…

A: Given data,Hence, Coefficient of permeability is 4 cm/s

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

A:

Q: Maximum and minimum void ratios of a sand sample were determined in the laboratory to be 0.9 and…

A: Given data : emin=0.3emax=0.9Void ratio of sand (e)=0.53

Q: A sample of soil compacted according to the standard Proct or test has a density of 2.06 g/cm³ at…

A: Dry Unit weight is given by ; γdry = γ1 + w where ; γ = ρg = 2.06 × 9.81 = 20.209 KN/m2 w = Water…

Q: The value of coefficient of permeability (in cm/s) of a uniformly graded sand of size D10 = 0.15 cm…

A: This question is related to Permeability from geotechnical engineering.

Q: Undisturbed soil sample was collected from the filed in Melbourne in steel tube for laboratory…

A: Diameter of the steel tube =  85 mmLength of steel tube= 170 mm (0.17 m)Moisture weight = 1600…

Q: The results of a standard compaction test for a soil having a value of (Gs = 2.5) are shown in the…

A: Given:- Specific gravity, Gs=2.5 Water Content (%) 6.2 8.1 9.8 11.5 12.3 13.2 Unit weight…

Q: The natural water content and in-situ unit weight of a sample of sand above water table are 14% and…

A: Given data : Void ratio in densest state emin=0.48 Void ratio in loosest state emax=0.80 Water…

Q: A loose uncompacted sand fill 5 ft in depth has a relative density of 40%. Laboratory tests…

A:

Q: The volume of a soil sample at the liquid limit (L.L = 50%) was 329.7 cm³ and the mass 570 gm. The…

A: Given data of soil sample :-  Liquid limit = 50% = 0.5  Volume of soil at liquid limit = 329.7 Cm3…

Q: Following are the results from the liquid and plastic limit tests for a soil. Liquid limit test:…

A: Given data  PL = 18.7%

Q: A sand sample has a porosity of 30% and specific gravity of solids as 2.6. What is its degree of…

A: given- porosity n=30%G=2.6moisture content w=4.94%

Q: Diaz (1992) reported the following values for Mexico City clay: void ratio (e) = 2, natural water…

A: To compute the remaining quantities entering a phase diagram, we can use the following formulas:1.…

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.