Following is a GLHP installed in a gymnasium. The gym needs cooling and the swimming pool water needs heating simultaneously. The ground loop is bypassed and Heat of Rejection of space cooling is rejected in the swimming pool water. The Heatpump is providing 16.0 kW of cooling to the cooling space. The heating power of the pool water is 5.86 Ton. (1 kw = 3412 BTU/h, 1kW=0.2843 Ton) Q: Calculate the COP,heating of the system. 45 F Heat from cooling building is rejected directly to pool Cooling on 90°F Heat pump
Following is a GLHP installed in a gymnasium. The gym needs cooling and the swimming pool water needs heating simultaneously. The ground loop is bypassed and Heat of Rejection of space cooling is rejected in the swimming pool water. The Heatpump is providing 16.0 kW of cooling to the cooling space. The heating power of the pool water is 5.86 Ton. (1 kw = 3412 BTU/h, 1kW=0.2843 Ton) Q: Calculate the COP,heating of the system. 45 F Heat from cooling building is rejected directly to pool Cooling on 90°F Heat pump
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:Following is a GLHP installed in a gymnasium. The gym needs cooling and the
swimming pool water needs heating simultaneously. The ground loop is bypassed
and Heat of Rejection of space cooling is rejected in the swimming pool water. The
Heatpump is providing 16.0 kW of cooling to the cooling space. The heating power
of the pool water is 5.86 Ton. (1 kw = 3412 BTU/h, 1kW=0.2843 Ton)
Q: Calculate the COP,heating of the system.
45°F
Heat from cooling building is rejected
directly to pool
Cooling on
90°F
Heat pump
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