Write the balanced equation for the following situation. List the reaction type.Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type:a. Combination Reactionb. Decomposition Reactionc. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reactione. Gaseous Reactionf. Neutralization Reactiong. Combustion ReactionFollow the format used in the image.1.29 dag of sodium chloride is reacted with 25.0 dag of silver nitrate 2. N₂ (g) + 3 H₂ (g) → 2 NH3 (g) (This is LIMITING REACTANT: N2 is the Limiting Reactant)Grams of Product (List the Product and the Amount): 0.75168 g NH3Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction)? g NH3 = 61.802 cg N₂ x 1g N₂2 mol NH3 x 17.04 g NH3 =1 mol N₂1 mol NH3LR? g NH3 = 61.802 cg H₂ xHow much N₂ remains in the vessel?1 x 10² cg N₂1 g H₂1 x 10² g H₂x 1 mol N₂ x28.02 g N₂XX1 mol H₂2.02 g H₂X2 mol NH3 x 17.04 g NH33 mol H₂1 mol NH3You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN.1 mol N₂ x 3 mol H₂ x 2.02 g H₂28.02 g N₂ 1 mol N₂ 1 mol H₂==0.75168 g NH30.75168 g? g H₂ USED= 61.802 cg N₂ x 1g N₂1 x 10² cg N₂Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED = 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED0.48436 g of H2--LEFT OVER = EXCESS=NH3 ******* THEORETICAL YIELD3.3756 g NH30.13366 g H₂

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Write the balanced equation for the following situation. List the reaction type.
Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!!

Reaction Type:
a. Combination Reaction
b. Decomposition Reaction
c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction
d. Precipitation Reaction
e. Gaseous Reaction
f. Neutralization Reaction
g. Combustion Reaction

Follow the format used in the image.

1.29 dag of sodium chloride is reacted with 25.0 dag of silver nitrate

2. N₂ (g) + 3 H₂ (g) → 2 NH3 (g) (This is LIMITING REACTANT: N2 is the Limiting Reactant)
Grams of Product (List the Product and the Amount): 0.75168 g NH3
Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction)
? g NH3 = 61.802 cg N₂ x 1g N₂
2 mol NH3 x 17.04 g NH3 =
1 mol N₂
1 mol NH3
LR
? g NH3 = 61.802 cg H₂ x
How much N₂ remains in the vessel?
1 x 10² cg N₂
1 g H₂
1 x 10² g H₂
x 1 mol N₂ x
28.02 g N₂
X
X
1 mol H₂
2.02 g H₂
X
2 mol NH3 x 17.04 g NH3
3 mol H₂
1 mol NH3
You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN.
1 mol N₂ x 3 mol H₂ x 2.02 g H₂
28.02 g N₂ 1 mol N₂ 1 mol H₂
=
=
0.75168 g NH3
0.75168 g
? g H₂ USED= 61.802 cg N₂ x 1g N₂
1 x 10² cg N₂
Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED = 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED
0.48436 g of H2--LEFT OVER = EXCESS
=
NH3 ******* THEORETICAL YIELD
3.3756 g NH3
0.13366 g H₂

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