Fluid motor system problem: Water at 10°C is flowing at a rate of 115 L/min through the fluid motor shown in figure below. The pressure at A is 700 kPa and the pressure at B is 125 kPa. It is estimated that due to friction in the tubing there is an energy loss of 4.0 N.m/N of water flowing. At A the tubing entering the fluid motor is a standard steel hydraulic tube having an OD = 25 mm and a wall thickness of 2.0 mm. At B, the tube leaving the motor has OD = 80 mm and wall thickness of 2.8 mm. (a) Calculate the power delivered to the fluid motor by the water. (b) If the mechanical efficiency of the fluid motor is 85 percent, calculate the power output. (For water at 10°C, y= 9.81 kN/m') HINT: USE THE GENERAL ENERGY EQUATION BETWEEN POINTS A & B TO FIND h. 25-mm OD PA/Y + ZA + v/2g +ha-hg - h = Pe/Y + Zg + vg/2g x 2.0-mm wall Flow BUT power delivered by a fluid to a motor is given by the following equation PR = hp x weight flow rate = Fluid motor ha Y Q 1.8 m Efficiency (eM) is given by the following equation em = Po/PR 80-mm OD CHECK BELOW ANSWER: x 2.8-mm wall Po=0.9256 Kw B WHAT IS THIS IN HORSEPOWER? 6.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Fluid motor system problem: Water at 10°C is flowing at a rate of 115 L/min through the fluid motor
shown in figure below. The pressure at A is 700 kPa and the pressure at B is 125 kPa. It is estimated
that due to friction in the tubing there is an energy loss of 4.0 N.m/N of water flowing. At A the tubing
entering the fluid motor is a standard steel hydraulic tube having an OD = 25 mm and a wall
thickness of 2.0 mm. At B, the tube leaving the motor has OD = 80 mm and wall thickness of 2.8
mm. (a) Calculate the power delivered to the fluid motor by the water. (b) If the mechanical efficiency
of the fluid motor is 85 percent, calculate the power output.
(For water at 10°C, y = 9.81 kN/m')
HINT:
USE THE GENERAL ENERGY EQUATION BETWEEN POINTS A & B TO FIND h,
PA/y + ZA + vA/2g +h - hg - h= Pg/Y+ Zg + v;²/2g
25-mm OD
x 2.0-mm wall
Flow
BUT power delivered by a fluid to a motor is given by the following equation
PR=hRX weight flow rate = h, y Q
Fluid motor
1.8 m
Efficiency (eM) is given by the following equation
eM =Po/PR
80-mm OD
x 2.8-mm wall
CHECK BELOW ANSWER:
Po= 0.9256 Kw
WHAT IS THIS IN HORSEPOWER?
6.
Transcribed Image Text:Fluid motor system problem: Water at 10°C is flowing at a rate of 115 L/min through the fluid motor shown in figure below. The pressure at A is 700 kPa and the pressure at B is 125 kPa. It is estimated that due to friction in the tubing there is an energy loss of 4.0 N.m/N of water flowing. At A the tubing entering the fluid motor is a standard steel hydraulic tube having an OD = 25 mm and a wall thickness of 2.0 mm. At B, the tube leaving the motor has OD = 80 mm and wall thickness of 2.8 mm. (a) Calculate the power delivered to the fluid motor by the water. (b) If the mechanical efficiency of the fluid motor is 85 percent, calculate the power output. (For water at 10°C, y = 9.81 kN/m') HINT: USE THE GENERAL ENERGY EQUATION BETWEEN POINTS A & B TO FIND h, PA/y + ZA + vA/2g +h - hg - h= Pg/Y+ Zg + v;²/2g 25-mm OD x 2.0-mm wall Flow BUT power delivered by a fluid to a motor is given by the following equation PR=hRX weight flow rate = h, y Q Fluid motor 1.8 m Efficiency (eM) is given by the following equation eM =Po/PR 80-mm OD x 2.8-mm wall CHECK BELOW ANSWER: Po= 0.9256 Kw WHAT IS THIS IN HORSEPOWER? 6.
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